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Alika [10]
2 years ago
15

Use this picture to explain that an electrically charged object can attract an uncharged object without any contact. Your answer

should be at least three sentences long.
a balloon hanging from a string with small pieces of paper stuck to the bottom of it, with a few pieces on the ground
Chemistry
1 answer:
Musya8 [376]2 years ago
6 0

Answer:

Explanation:

......where's the picture--

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How did Mendeleev arrange the known elements?
Agata [3.3K]
In order of relative atomic mass.
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If 9.5 × 10²⁵ molecules of CO₂ are produced in a combustion reaction, what is the mass in kg of CO₂ that is produced?
Leno4ka [110]

Answer:

6.9428 kg of CO2

Explanation:

1) Use Avogadro's number that states 1 mole = 6.022 x 10^23 particles. Convert 9.5 x 10^25 molecules into moles.

9.5 x 10^25 CO2 moleculesx\frac{1 mole CO2}{6.022 x 10^23} = 157.75 moles CO2

2) Convert 157.75 moles of CO2 into grams. CO2's molar mass is 44.01g.

157.75moles CO2 x \frac{44.01g/mol}{1 mole CO2} = 6942.79g

3) Convert 6942.79 grams into kilograms (divide by 1000):

6.9428 kg

4 0
2 years ago
How many electrons are contained in a co3+ ion
Mumz [18]
The atomic number of cobalt, CO is 27. Since, the cobalt that you asked is in ion. The number of electrons should be 27-3 --> *24* Reasons being that cobalt has donated/given away 3 electrons.
7 0
2 years ago
The combustion of how many moles of ethane (C2H6) would be required to heat 851 g of water from 25.0°C to 98.0°C? (Assume liquid
Debora [2.8K]

Answer : The number of moles of ethane required will be 0.166 mole.

Explanation :

First we have to calculate the heat absorbed by water.

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat absorbed = ?

m = mass of water = 851 g

c = specific heat of water = 4.18J/g^oC

T_{final} = final temperature = 98.0^oC

T_{initial} = initial temperature = 25.0^oC

Now put all the given values in the above formula, we get:

q=851g\times 4.18J/g^oC\times (98.0-25.0)^oC

q=259674.14J=259.67kJ         (1 kJ = 1000 J)

Now we have to calculate the moles of ethane required.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of combustion of ethane = 1560.7 kJ/mol (standard value)

q = heat absorbed = 259.67 kJ

n = number of moles of ethane = ?

1560.7kJ/mol=\frac{259.67kJ}{n}

n=\frac{259.67kJ}{1560.7kJ/mol}

n=0.166mole

Therefore, the number of moles of ethane required will be 0.166 mole.

8 0
2 years ago
What is the molar mass of (NH4)3PO4
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Answer:

the molar mass of (NH4)3PO4 is 149.09 g/mol

8 0
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