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Nonamiya [84]
3 years ago
11

An inexperienced chemist adds too little boiling solvent to an impure sample of product and then leaves this mixture to cool. th

e crystals form with product coated onto impure crystals. that form are pure. do not form. form with impurities coated onto the pure crystals
Chemistry
1 answer:
Gala2k [10]3 years ago
6 0

Recrystallization of a solid is an experimental technique used to separate out impurities from a pure product using differential solubilities of the solids in a solvent at different temperatures. We chose a solvent in which the pure solid has lower solubility at low temperatures but is completely soluble at higher temperatures. The amount of solvent taken must be sufficient to completely dissolve the impure solid formed in a reaction. The impurities must be soluble in cold solvent, so that they can remain in solution after crystallization of pure compound.  When the amount of solvent is too little then we cannot achieve the separation of pure crystals as the pure solid crystallizes on the impurities.

So the correct answer will be the crystals form with product coated onto impure crystals

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What is the mass of a sample of alcohol (specific heat = 2.4 J/gC), if it requires 4780 J of heat to raise the temperature by 5.
insens350 [35]

The mass of a sample of alcohol is found to be = m = 367 g

Hence, it is found out that by raising the temperature of the given product, the mass of alcohol would be 367 g.

Explanation:

The Energy of the sample given is q = 4780

We are required to find the mass of alcohol m = ?

Given that,

The specific heat given is represented by = c = 2.4 J/gC

The temperature given is ΔT = 5.43° C

The mass of sample of alcohol can be found as follows,

The formula is c = \frac{q}{mt}

We can drive value of m bu shifting m on the left hand side,

m = \frac{q}{ct}

mass of alcohol (m) = \frac{4780}{(2.4)( 5.43)}

m = 367 g

Therefore, The mass of the given sample of alcohol is

m = 367g

It requires 4780 J of heat to raise the temperature by 5.43 C in the process which yields a mass of 367 g of alcohol.

4 0
3 years ago
A. 25.0 ml of a solution of sodium hydroxide solution required 21.50 ml of 0.100 mol/l sulphuric acid for neutralisation.
nexus9112 [7]

The concentration of the sodium hydroxide solution in mol/l is 0.176 M.

Concentration is the abundance of a constituent divided by way of the overall volume of an aggregate. several sorts of mathematical descriptions may be outstanding: mass concentration, molar concentration, variety concentration, and extent awareness.

Given

V =25 ml = 0.025 L

M = 0.1

C₁ = 0.1

V₁ = 21.50 = 0.022 L

C₂ = ?

V₂ = 25 ml = 0.025 L

C₁V₁ = C₂V₂

C₂ = C₁V₁ / V₂

   = 0.1 * 0.022 * 2 / 0.025

   =  0.176 M

The concentration of a substance is the quantity of solute found in a given amount of solution. Concentrations are normally expressed in terms of molarity, defined because of the variety of moles of solute in 1 L of answer.

The Concentration of an answer is a measure of the quantity of solute that has been dissolved in a given amount of solvent or answer. A concentrated answer is one that has a rather huge quantity of dissolved solute.

Learn more about concentration here:-brainly.com/question/26255204

#SPJ1

3 0
10 months ago
what temperature change will be observed if a sample of 100 g of ethylene glycol antifreeze solution (specific heat capacity = 3
ivolga24 [154]

Answer:

1°C temperature change will be observed if a sample of 100 g of ethylene glycol antifreeze solution.

Explanation:

Mass of ethylene glycol = m = 100 g

Specific heat capacity of ethylene glycol = c = 3.5 J/g°C

Change in temperature of ethylene glycol = ΔT

Heat loss by the ethylene glycol = Q = 350 J

Q=mc\Delta T

\Delta T=\frac{Q}{mc}=\frac{350 J}{100 g\times 3.5 J/g^oC}

ΔT = 1°C

1°C temperature change will be observed if a sample of 100 g of ethylene glycol antifreeze solution.

3 0
3 years ago
ICl has a higher boiling point than Br2. What is the best explanation for this?
Flura [38]
<span>The best answer is B. ICl experiences induced dipole-induced dipole interactions. Both iodine and chlorine belongs to the same group of the periodic table. Electronegativity decreases as you go down a group therefore Cl will have a greater attraction with the bond it forms with another atom. Dipole-dipole interactions form between I and Cl. For the Br2 molecule, no dipole occurs because they are two identical atoms. Therefore we will be expecting ICl will have a higher boiling point due to higher binding energy it forms.</span>
7 0
3 years ago
Diatomic iodine [I2] decomposes at high temperature to form I atoms according to the reaction I2(g)⇌2I(g), Kc = 0.011 at 1200∘C
umka2103 [35]

Answer:

The concentration of I at equilibrium = 3.3166×10⁻² M

Explanation:

For the equilibrium reaction,

I₂ (g) ⇄ 2I (g)

The expression for Kc for the reaction is:

K_c=\frac {\left[I_{Equilibrium} \right]^2}{\left[I_2_{Equilibrium} \right]}

Given:

\left[I_2_{Equilibrium} \right] = 0.10 M

Kc = 0.011

Applying in the above formula to find the equilibrium concentration of I as:

0.011=\frac {\left[I_{Equilibrium} \right]^2}{0.10}

So,

\left[I_{Equilibrium} \right]^2=0.011\times 0.10

\left[I_{Equilibrium} \right]^2=0.0011

\left[I_{Equilibrium} \right]=3.3166\times 10^{-2}\ M

<u>Thus, The concentration of I at equilibrium = 3.3166×10⁻² M</u>

3 0
3 years ago
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