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3 years ago

2.1•10^-3 written in standard form PLEASE HELP FAST

Mathematics

1 answer:

White raven [17]3 years ago

4 0

Answer:

0.0021

Step-by-step explanation:

move decimal three to the left

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Describe 2 real world situation that could be modeled by a quadratic function

Naya [18.7K]

Solution:

1. Consider two trees which are 5 m apart. Suppose one tree is located at a distance of 45 m from my house and another tree is located 50 m from my house. Represent , distance of two trees from my house in terms of Quadratic function.

Solution:

Let location of my house when map of planet earth is drawn or on globe=x

⇒(x-45)(x-50)=0

⇒ x² - 45 x - 50 x +45 × 50 =0

⇒ x² - 95 x + 2250=0

2. Suppose age of me and my brother is 6 and 10 years. The Product of difference between age of me and my mother who is x years old and my brother and mother is 780.Find my mother's age.

Solution: Age of my mother = x years

→(x-6) × (x-10)= 780,

if you will solve it , the value of x= 36 years

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3 years ago

Help please thank you!

irga5000 [103]

Answer:

Step-by-step explanation:

W(-4,-10) lies on third quadrant.

M(-12,0) lies on second quadrant or can say in x axis

C(8,3) lies on first quadrant.

K(11,-5) lies on fourth quadrant.

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2 years ago

Help please bed asap thank you!!!

Mkey [24]

Answer:

Step-by-step explanation:

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1 year ago

The functions f (theta) and g (theta) are sine functions, where f (0) equals g (0) equals 0.The amplitude of f (theta) is twice

777dan777 [17]

If period of $f(\theta)$ is one-half the period of $g(\theta)$ and
 $g(\theta)$ has a period of 2π, then $T_{g} =2T_{f}=2 \pi$ and $T_{f}= \pi$ .

To find the period of sine function $f(\theta)=asin(b\theta+c)$ we use the rule $T_{f}= \frac{2\pi}{b}$ .

f is sine function where f (0)=0, then c=0; with period $\pi$ , then $f(\theta)=asin 2\theta$ , because $T_{f}= \frac{2 \pi }{2} = \pi$ .

To find a we consider the condition $f( \frac{ \pi }{4} )=4$ , from where $asin2* \frac{\pi}{4} =a*sin \frac{ \pi }{2} =a=4$ .

If the amplitude of $f(\theta)$ is twice the amplitude of $g(\theta)$ , then $g(\theta)$ has a product factor twice smaller than $f(\theta)$ and while period of $g(\theta)$ is 2π and g(0)=0, we can write $g(\theta)=2sin\theta$ .

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2 years ago

The area of a rectangle is 27 m^2 , and the length of the rectangle is 3 m less than twice the width. Find the dimensions of the

vagabundo [1.1K]

Let $L$ be the length of the rectangle and $W$ be the width. In the problem it is given that $L=2W-3$ . It is also given that the area $LW=27$ . Substituting in the length in terms of width, we have $W(2W-3)=27 \\ 2W^2-3W-27=0 \\ (2W-9)(W+3)=0$ . Using the zero product property, $2W-9=0 \text{ or } W+3=0$ . Solving these we get the width $W=4.5 \text{ or } -3$ . However, it doesn't make sense for the width to be negative, so the width must be $\boxed{4.5 \text{ m}}$ . From that we can tell the length $L=2(4.5)-3=\boxed{6 \text{ m}}$ .

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2 years ago