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Allushta [10]
3 years ago
13

2.1•10^-3 written in standard form PLEASE HELP FAST

Mathematics
1 answer:
White raven [17]3 years ago
4 0

Answer:

0.0021

Step-by-step explanation:

move decimal three to the left

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7n2 + 5 = 453<br> Solve the quadratic function
Reptile [31]

7n^2 + 5 = 453

Subtract 5 from both sides:

7n^2 = 448

Divide both sides by 7:

N^2 = 64

Take the square root of both sides:

N = 8

8 0
3 years ago
Read 2 more answers
If fx = 3x over 5 +3 which of the following is the inverse
Alborosie

Answer:

f^(-1)(x) = -3x/(3x-3)

Step-by-step explanation:

1) replace f(x) by y

● y = 3x/(5x+3)

2) exchange x and y

● y = 3x/(5x+3)

● x = 3y / (3y +3)

3) solve for y

● x = 3y / (3y +3)

● x (3y +3) = 3y

● 3xy + 3x = 3y

● 3xy - 3y = -3x

● y (3x - 3) = -3x

● y = -3x /(3x-3)

4) replace y with f^(-1)(x)

● y = -3x/(3x-3)

● f^(-1)(x) = -3x/(3x-3)

3 0
3 years ago
There is a bag filled with 3 blue and 4 red marbles. A marble is taken at random from the bag, the colour is noted and then it i
Morgarella [4.7K]

altogether there are 7 marbles in the bag.

put the marbles in fractions, so blue would be 3/7

and red would be 4/7. but becuase you need 2 of the same, you do

3/7 x 3/7 = 9/49

4/7 x 4/7 = 16/49

then add them togther

25/49

if you need it as a percentage, it is

51.020408163265%

8 0
3 years ago
Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?
Bogdan [553]

Step-by-step explanation:

\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}

\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}

\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}

\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}

Taking sin²θ common in both numerator & denominator, We get :

\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{cot\theta = \dfrac{cos\theta}{sin\theta}}}}

\mathsf{\implies \dfrac{1 -cot^2\theta}{1 + cot^2\theta}}

\mathsf{Given :\;cot\theta = \dfrac{1}{\sqrt{5}}}

\mathsf{\implies \dfrac{1 - \left(\dfrac{1}{\sqrt{5}}\right)^2}{1 + \left(\dfrac{1}{\sqrt{5}}\right)^2}}

\mathsf{\implies \dfrac{1 - \dfrac{1}{5}}{1 + \dfrac{1}{5}}}

\mathsf{\implies \dfrac{\dfrac{5 - 1}{5}}{\dfrac{5 + 1}{5}}}

\mathsf{\implies \dfrac{5 - 1}{5 + 1}}

\mathsf{\implies \dfrac{4}{6}}

\mathsf{\implies \dfrac{2}{3}}

<u>Hence</u><u>,</u><u> option</u><u> </u><u>(</u><u>a)</u><u> </u><u>2</u><u>/</u><u>3</u><u> </u><u>is </u><u>your</u><u> </u><u>correct</u><u> </u><u>answer</u><u>.</u>

3 0
3 years ago
The ratio of your monthly allowance to your friend’s monthly allowance is 5 : 3. If your friend received a monthly allowance of
Sever21 [200]

Answer:

i recience 10 dollars

Step-by-step explanation:

5 0
3 years ago
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