No volcanoes are formed by tectonic plates down below the ground
Answer:
Xe will have the highest partial pressure
Explanation:
Using Dalton's law of partial pressures for ideal gases
p=P*x
where
p= partial pressure , P= total pressure and x = mole fraction = n / ∑n
since the number of moles is related with mass through
n= m/M
where
m= mass and M= molecular weight
then if m is the same for all the gases
x = m*M/ ∑ (m*M) = m*M/ m∑ M = M/∑ M
thus
p=P*x = P*M/ ∑ M
for the 3 gases
p₁=P*x₁ = P*M₁/ (M₁+M₂+M₃)
p₂=P*x₃ = P*M₂/ (M₁+M₂+M₃)
p₂=P*x₃ = P*M₃/ (M₁+M₂+M₃)
then for gasses under the same pressure (P=constant) and same mass (m=constant) , p is higher when the molecular weight is higher . Therefore Xe will have the highest partial pressure
The answer is theory because it says if and that means theory
Answer:
See explanation below
Explanation:
The question is incomplete. However, here's the missing part of the question:
<em>"For the following reaction, Kp = 0.455 at 945 °C: </em>
<em>C(s) + 2H2(g) <--> CH4(g). </em>
<em>At equilibrium the partial pressure of H2 is 1.78 atm. What is the equilibrium partial pressure of CH4(g)?"</em>
With these question, and knowing the value of equilibrium of this reaction we can calculate the partial pressure of CH4.
The expression of Kp for this reaction is:
Kp = PpCH4 / (PpH2)²
We know the value of Kp and pressure of hydrogen, so, let's solve for CH4:
PpCH4 = Kp * PpH2²
*: You should note that we don't use Carbon here, because it's solid, and solids and liquids do not contribute in the expression of equilibrium, mainly because their concentration is constant and near to 1.
Now solving for PpCH4:
PpCH4 = 0.455 * (1.78)²
<u><em>PpCH4 = 1.44 atm</em></u>
