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zzz [600]
2 years ago
9

Explain how a drought poses a threat to life and the biosphere. Use complete sentences.

Chemistry
2 answers:
Marina CMI [18]2 years ago
6 0

Answer:

A drought poses a huge threat to all life. If a drought occurred the entire food chain would disintegrate within months. There would be no water for any animals or plants. Small mammals would not be able to eat plants, and reptiles would not be able to the small animals, and so on. A drought can destroy an ecosystem in a short amount of time.

Water is only being moved into the air through water vapor, so the air will become hotter than water. Land is also not moving in the atmosphere and absorbing heat like air is, so air will also be hotter than land, depending on what the land is made of.

Through precipitation, water in the atmosphere can return to the hydrosphere or percolate into the ground to become groundwater—part of the geosphere. ... Water in the biosphere can be released into the atmosphere through transpiration in plants, or respiration in animals.

Explanation:

Arte-miy333 [17]2 years ago
5 0

Answer:

There would be no water for animals and plants, so life would die out.

(I added this on my test.)

Explanation:

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I believe the answer is B!
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Who first argued that all matter is made up of particles so small that they could not possibly be divided
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1. How do metals and non-metals react with acids? Write and explain the chemical equation for the reaction of magnesium with sul
Nata [24]

Answer:

1. How do metals and non-metals react with acids?

Ans : Non metals does not react with acids while metals react with acids and produce hydrogen gas that burns with a 'pop'sound.

2. Write and explain the chemical equation for the reaction of magnesium with sulphuric acid and aluminium with hydrochloric acid.

Magnesium + sulphuric acid = Hydrogen + salt

Mg(s) + H2SO4 (aq) MgSO 4(aq) +H2 (g)

Aluminium + Hydrochloric acid = Hydrogen + Aluminium chloride

2Al(s)+6HCl(aq)→2AlCl3(aq)+3H2(g)

6 0
3 years ago
Read 2 more answers
A student uses a sample of KOH stock solution and dilutes it to a total of 120 mL. If the diluted solution is 0.60 M KOH and its
Vesnalui [34]

Answer:

5.5

Explanation:

i think so?????????

5 0
3 years ago
A rigid 3.80 L sealed vessel contains 0.650 mol Ne, 0.321 mol Kr, and 0.190 mol Xe. Find the density of the mixture in g/L.
Eddi Din [679]

Answer:

17.09g/L

Explanation:

Density = total mass of elements/ volume

We need to find the mass of each mixture constituents using their molar mass:

mole = mass/molar mass

For Neon (Ne) which contains 0.650mol;

0.650 = mass/20.18

mass = 0.650 × 20.18

mass = 13.12g

For Krypton (Kr) which contains 0.321mol;

0.321 = mass/83.79

mass = 0.321 × 83.79

mass = 26.89g

For Xenon (Xe) which contains 0.190mol;

0.190 = mass/131.3

mass = 0.190 × 131.3

mass = 24.95g

Total mass = 13.12g + 26.89g + 24.95g = 64.96g

Density = total mass / volume

Density = 64.96g / 3.80L

Density of the mixture = 17.09g/L

7 0
3 years ago
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