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3 years ago

Explain how a drought poses a threat to life and the biosphere. Use complete sentences.

Chemistry

2 answers:

Marina CMI [18]3 years ago

6 0

Answer:

A drought poses a huge threat to all life. If a drought occurred the entire food chain would disintegrate within months. There would be no water for any animals or plants. Small mammals would not be able to eat plants, and reptiles would not be able to the small animals, and so on. A drought can destroy an ecosystem in a short amount of time.

Water is only being moved into the air through water vapor, so the air will become hotter than water. Land is also not moving in the atmosphere and absorbing heat like air is, so air will also be hotter than land, depending on what the land is made of.

Through precipitation, water in the atmosphere can return to the hydrosphere or percolate into the ground to become groundwater—part of the geosphere. ... Water in the biosphere can be released into the atmosphere through transpiration in plants, or respiration in animals.

Explanation:

Arte-miy333 [17]3 years ago

5 0

Answer:

There would be no water for animals and plants, so life would die out.

(I added this on my test.)

Explanation:

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NH3 1. Lewis Structure 2. Perspective drawing 3. Number of atoms bonded to central atom 4. Number of non-bonding electron pairs

Stels [109]

This question will be answered in parts:

<h3><u>1. Lewis Structure</u></h3>

There are three N-H bonds and one lone pair on the nitrogen atom in the Lewis structure of NH3. On hydrogen atoms, there are no lone pairs that can only hold two electrons.

The lewis structure is as shown in the diagram.

<h3><u>2. Perspective Drawing</u></h3>

A molecule is shown from a viewpoint with its atoms' bonds pointing either in your direction (bolded wedge) or away from you (hash wedge).

The perspective drawing of NH3 is given here

<h3><u>3.Number of atoms bonded to central atom </u></h3>

Nitrogen is the central atom in the Lewis structure of NH3, which also contains one lone pair and is bound to the three hydrogen atoms.

<h3><u>4.Number of non-bonding electron pairs on the central atom</u></h3>

Three bond pairs and two lone pairings exist. This is due to the fact that nitrogen contains five electrons in its outer shell, three of which are bound to hydrogen atoms and two of which are free.

<h3><u>5. Electronic geometry:</u></h3>

The electronic geometry of nitrogen is based on a tetrahedral arrangement of electron pairs, and ammonia likewise possesses four electron pairs. There is only one lone pair because there are only three connected groupings. But since the lone pairs are "invisible," the ammonia has a pyramidal form.

<h3><u>6. Molecular geometry with ideal bond angles</u></h3>

The molecular geometry of ammonia it has a trigonal pyramidal or distorted tetrahedral structure.

The bond angle in ammonia is less than the standard 109.5⁰. The bond angle is 107⁰

<h3><u>7.Hybridization of central atom</u></h3>

The core nitrogen (N) atom in the NH3 molecule has a steric number of (3 + 1) = 4, which causes Sp3 hybridization.

<h3><u>8. Polarity:</u></h3>

Because of its asymmetrical form, a trigonal pyramidal structure, and the different electronegativities of N(3.04) and H(2.2), the NH3 (ammonia) molecule is polar in nature .

To know more about ammonia, you can refer to:

brainly.com/question/13960908

#SPJ4

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1 year ago

Which statement is true about BF3, a nonpolar molecule? It has nonpolar bonds and a symmetrical structure. It has nonpolar bonds

konstantin123 [22]

I think the correct answer is the first option. It has nonpolar bonds and a symmetrical structure. The structure of a BF3 molecule shows a symmetrical trigonal geometry. The net dipole moment of the molecule is zero therefore it is polar.

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3 years ago

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How many moles of gas does it take to occupy 120 L at a pressure of 233 kPa and a temperature of 340 K?

natka813 [3]

A would be correct have a nice day.

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3 years ago

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A nuclear reactor core must stay at or below 95 °C to remain in good working condition. Cool water at a temperature of 10 °C is

aliina [53]

Answer:

$\large \boxed{\text{67 000 g}}$

Explanation:

This is a problem in calorimetry — the measurement of the quantities of heat that flow from one object to another.

It is based on the Law of Conservation of Energy — Energy can be transformed from one type to another, but it cannot be destroyed or created.

If heat flows out of the reactor (negative), the same amount of heat must flow into the water (positive).

Since there is no change in total energy,

heat₁ + heat₂ = 0

The symbol for the quantity of heat transferred is q, so we can rewrite the word equation as

q₁ + q₂ = 0

The formula for the heat absorbed or released by an object is

q = mCΔT, where

m = the mass of the sample

C = the specific heat capacity of the sample, and

ΔT = T_f - T_i = the change in temperature

1. Equation

There are two heat flows in this problem,

heat released by reactor + heat absorbed by water = 0

q₁ + q₂ = 0

q₁ + m₂C₂ΔT₂ = 0

2. Data:

q₁ = -23 746 kJ

m₂ = ?; C₂ = 4.184 J°C⁻¹g⁻¹; T_f = 95 °C; T_i = 10 °C

3. Calculations

(a) Convert kilojoules to joules

$q_{1} = -\text{23 746 kJ} \times \dfrac{\text{1000 J}}{\text{1 kJ}} = -\text{23 746 000 J}$

(b) ΔT

ΔT₂ = T_f - T_i = 95 °C - 10 °C = 85 °C

(c) m₂

$\begin{array}{rcl}q_{1} + q_{2} & = & 0\\\text{-23 746 000 J} + m_{2} \times 4.184 \text{ J$^{\circ}$C$^{-1}$g$^{-1}$} \times 85 \, ^{\circ}\text{C} & = & 0\\\text{-23 746 000 J} + 356m_{2} \text{J$\cdot$g}^{-1} & = & 0\\356m_{2} \text{g}^{-1} & = & 23746000\\m_2&=& \dfrac{23746000}{\text{356 g}^{-1}}\\\\ & = & \textbf{67000 g}\\\end{array}\\$

$\text{You must circulate $\large \boxed{\textbf{67 000 g}}$ of water each hour.}$

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3 years ago

Using the process of photosynthesis, describe how carbon and oxygen cycles interact

Alex777 [14]

In photosynthesis, plants take in carbon dioxide and turn it into energy that comes out as oxygen.

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3 years ago

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