<u>Answer:</u>
A. Solution of copper (II) sulfate reacts with solution of sodium hydroxide to produce "copper hydroxide & solution of sodium sulphate".
B. Solid baking soda (sodium hydrogen carbonate or sodium bicarbonate) reacts with solution of hydrochloric acid to produce "carbon dioxide and water".
<u>Explanation:</u>
When CuSO4 is an acid salt while NaOH is a solid base mixed together. This reaction results into a basic copper hydroxide in the form of pale blue precipitate & sodium sulphate, which is a solution of neutral salt. This process is called as both a double displacement and precipitation reaction.
2NaOH + CuSO4 --> Cu(OH)2 + Na2SO4.
Sodium bicarbonate is used as a cleaner, from a "primitive" material to extract any acidic contaminants, for producing a nobler sample. Sodium bicarbonate and acid mixture generates a salt and carbonic acid that breaks down readily into carbon dioxide and water.
NaHCO3 + HCl → NaCl + H2CO. H2CO3 → H2O + CO2(g).
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The number of mole of copper in the sample is 0.008 mole.
Mole is simply defined as the unit of amount in a substance.
The mole of a substance can be obtained by dividing the mass of the subtance by its molar mass i.e
Mole = mass / molar mass
With the above information, we can obtain the mole of copper in the compound as follow:
Mass of copper = 0.5066 g
Molar mass of copper = 63.5 g/mol
<h3>Mole of copper =? </h3>
Mole = mass / molar mass
Mole of copper = 0.5066 / 63.5
<h3>Mole of copper = 0.008 mole </h3>
Therefore, 0.008 mole of copper was initially present in the compound.
Learn more: brainly.com/question/14295066
