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3 years ago

In an atom of barium, how many electrons have: ℓ = 0 mℓ = 1

Chemistry

1 answer:

expeople1 [14]3 years ago

5 0

First look for the atomic number and that is the electron for barium

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Calculate the number of oxygen atoms and its mass in 50g of CaCo3<br>

xz_007 [3.2K]

The number of oxygen atoms = 3

Mass = 24 g

<h3>Further explanation</h3>

The formula of a compound shows the composition of the constituent elements

CaCO₃ is composed of 3 types of elements, namely Ca, C and O

The amounts of each of these elements in the compound CaCO₃:

Ca = 1
C = 1
O = 3

So the number of oxygen atoms = 3

mass of Oxygen :

$\tt mass~O=\dfrac{3\times Ar~O}{MW~CaCO_3}\times mass~CaCO_3\\\\mass~O=\dfrac{3\times 16}{100}\times 50=24~g$

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2 years ago

Which best describes a chemical reaction that follows the law of conservation of matter?

Leno4ka [110]

I’m thinking C for this hope it’s right

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3 years ago

Describe the chemical reaction based on the chemical equation below also whether the equation is balanced

Crank

Answer:

Its not balanced

4NH₃ + 7O₂ ⇒ 4NO + 6H₂O

3 0

3 years ago

Which property would cesium most likely have?

Romashka-Z-Leto [24]

The answer is a because its not low ductile or gasst

8 0

3 years ago

Read 2 more answers

A pharmaceutical company is making a large volume of nitrous oxide (NO). They predict they will be able to make a maximum amount

iragen [17]

Answer:

The answer is "Option B"

Explanation:

From the query, the following knowledge is derived:

Yield in percentage = 47%

Performance of theory = 4860 g

Actual yield Rate =?

The percentage return is defined simply by the ratio between both the real return as well as the conceptual return multiplied by the 100. It's also represented as numerically:

$Rate = \frac{Existing \ Rate} {Theoretical \ Rate} \times 100$

Now We can obtain the percent yield as followed using the above formula:

$\text{Yield in percentage}= \frac{Actual \ yield \ Rate} {Theorical \ Rate} \times 100$

$47\% = \frac{Actual \ yield \ Rate}{4860}$

The value of the Actual yield Rate = $47\% \times 4860$

$= \frac{47}{100} \times 4860 \\\\ = 2284.2 g$

The Actual yield Rate= 2284.2 g.

3 0

2 years ago