Answer:
its molecular formula must be C10H16O with 2 rings.
Explanation:
the number of rings of the camphor has to be calculated, we have M + = 152.12 in the mass spectrum and it has three double bonds and one ring. The base beak has great abundance.
Since camphor is a single ketone, and M+/MC = 12 ~~ 8, its molecular formula must be C10H16O, accordingly, the number of rings = (10 * 2-16)/2 = 2.
We call these reactive elements, becausethese atoms really like to follow the buddysystem and form bonds with other atoms.Noble gases, however, don't have thisproblem. Their outer shells are filled to the max, so they don't need to bond or react with any other atoms.
