Answer:
- Current market value of silver produced in the experiment = $0.2763
- Check Explanation for the appearance of leftover copper wire used in the experiment.
Explanation:
Price of Silver on today's market = $15.34 per troy ounce
Amount of Silver produced in the experiment = 0.56 g
31.1 g = 1 troy ounce
0.56 g = (0.56/31.1) = 0.01801 troy ounce
1 troy ounce = $15.34
0.01801 troy ounce = 0.01801 × $15.34 = $0.2763
The original reaction to extract the silver is one between Copper metal and the Silver Nitrate.
The Copper metal dissolves in the Silver Nitrate to give Copper Nitrate thereby displacing the Silver ion to become silver metal which we just valued above. But copper nitrate is a blue solution, So, it is a good estimate to say that the entire solution changed to that blue colour and the appearance of the leftover copper metal is colour blue. The silver metal forms as fractal-like crystals on this leftover copper.
Hope this Helps!!!
1) ideal gas law: p·V = n·R·T.
p - pressure of gas.
V -volume of gas.
n - amount of substance.
R - universal gas constant.
T - temperature of gas.
n₁ = 0,04 mol, V₁ = 0,06 l.
n₂ = 0,07 mol, V₂ = 0,06 · 0,07 ÷ 0,04 = 0,105 l.
2) V₁ = 0,06 l, T₁ = 240,00 K.
T₂ = 340,00 K, V₂ = 340 · 0,06 ÷ 240 = 0,05 l.
Answer:
the answer to the qustion is 0.013089701 na
Explanation:
n/a
NH₃:
N = 8*10²²
NA = 6.02*10²³
n = N/NA = 8*10²²/6.02*10²³ ≈ 1.33*10⁻¹=0.133mol
O₂:
N=7*10²²
NA = 6.02*10²³
n = N/NA = 7*10²²/6.02*10²³ = 1.16*10⁻¹=0.116mol
4NH₃ <span>+ 3O</span>₂ ⇒<span> 2N</span>₂<span> + 6H</span>₂<span>O
</span>4mol : 3mol : 2mol
0.133mol : 0.116mol : 0,0665mol
limiting reactant
N₂:
n = 0.0665mol
M = 28g/mol
m = n*M = 0.0665mol*28g/mol = <u>1,862g</u>
Transition metals usually
