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3 years ago

What type of waves are sound waves?

Chemistry

2 answers:

luda_lava [24]3 years ago

6 0

Heya!!!

Answer to your question:

D)transverse

Sound waves are transverse waves.

Hope it helps ^_^

malfutka [58]3 years ago

6 0

Answer: Transverse

Definition of Transverse: A wave vibrating at right angles to the direction of its propagation.

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A negatively charged balloon has 2.6 µc of charge. how many excess electrons are on this balloon? the elemental charge is 1.6 ×

Salsk061 [2.6K]

The given 2.6 µC of charge is due to a buildup of electrons, each of which has a charge of 1.6 x 10^-19 C. The 2.6 µC is equivalent to 2.6 x 10^-6 C, so we can divide this by the individual charge of an electron:
2.6 x 10^-6 C / 1.6 x 10^-19 (C/electron) = 1.625 x 10^13 electrons

5 0

3 years ago

How do potential energy diagrams represent energy transfer in chemical reactions?

Digiron [165]

Answer:

Hope this helps

Explanation:

Potential energy diagrams represent the energy transfer in chemical reactions in a diagram called a potential energy graph and/or a reaction progress curve. A potential energy diagram shows the adjustment in potential energy of a system as reactants are changed.

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2 years ago

Standard temperature and pressure (STP), in the context of gases, refers to a) 298.15 K and 1 atm b) 273.15 K and 1 atm c) 298.1

lina2011 [118]

Answer : The correct option is, (B) 273.15 K and 1 atm

Explanation :

STP : STP stands for standard temperature and pressure.

STP conditions :

The temperature is, $0^oC$ or $273.15K$ or $32^oF$

The pressure is, $1atm$ or $101.325kPa$

The volume is 22.4 L for 1 mole of a substance.

Hence, the correct option is, (B) 273.15 K and 1 atm

7 0

2 years ago

Help me if you can please help me please

Dovator [93]

Answer: with? i can help:))

Explanation:

hmu love

8 0

2 years ago

Read 2 more answers

2.00 L of 0.800 M NaNO3 must be prepared from a solution known to be 2.50 M in concentration.How many mL are required? Plus don'

Morgarella [4.7K]

Answer:

1.36 × 10³ mL of water.

Explanation:

We can utilize the dilution equation. Recall that:

$\displaystyle M_1V_1= M_2V_2$

Where M represents molarity and V represents volume.

Let the initial concentration and unknown volume be M₁ and V₁, respectively. Let the final concentration and required volume be M₂ and V₂, respectively. Solve for V₁:

$\displaystyle \begin{aligned} (2.50\text{ M})V_1 &= (0.800\text{ M})(2.00\text{ L}) \\ \\ V_1 & = 0.640\text{ L} \end{aligned}$

Therefore, we can begin with 0.640 L of the 2.50 M solution and add enough distilled water to dilute the solution to 2.00 L. The required amount of water is thus:
$\displaystyle 2.00\text{ L} - 0.640\text{ L} = 1.36\text{ L}$

Convert this value to mL:
$\displaystyle 1.36\text{ L} \cdot \frac{1000\text{ mL}}{1\text{ L}} = 1.36\times 10^3\text{ mL}$

Therefore, about 1.36 × 10³ mL of water need to be added to the 2.50 M solution.

8 0

1 year ago