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andre [41]
3 years ago
15

How many electrons does each gold atom gain? How many electrons does each iodine atom lose? What is the total number of electron

s that are moved in the oxidation-reduction reaction? Complete the final balanced equation based on the half-reactions.
Chemistry
2 answers:
gulaghasi [49]3 years ago
7 0

Answer:

3 , 1 , 6 , 2 , 6 , 2 , 3 , 6

forsale [732]3 years ago
6 0

Answer:

Explanation:

Half equation:

I. Au3+ + 3e- --> Au

II. 2I- --> I2 + 2e-

Au3+ + 3e- --> Au. ×2

2I- --> I2 + 2e- ×3

2Au3+ + 6e- --> 2Au

6I- --> 3I2 + 6e-

Overall equation

AuI3 --> 2Au + 3I2

A.

3 electrons

B.

2 electrons

C.

6 electrons

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irinina [24]

Answer:

you can do a celser lava lamp its really easy, i can give you a link if you need?

Explanation:

3 0
3 years ago
A student is shown a simple model of particles that make up a liquid,as shown.
trapecia [35]
Answer:
            Option-D : <span>Decrease the velocities of the particles, and decrease the space between the particles.

Explanation:
                     The solid state of matter is composed of particles closely packed with a minimum space between them. This closed packing of particles occur due to strong interatomic or intermolecular interactions between particles. Therefore, solids particles have zero translational and rotational motions and only show vibrational motions. So, decrease in velocity and decrease in space between particles is the right answer for making solids.</span>
6 0
3 years ago
An example of basic research is A) the development of new plastics that can be recycled. B) the study of the relationship betwee
elena-s [515]

Answer:

C) the study of the composition of the atom.

Explanation:

A research can be defined as a systematic investigation or careful consideration of study with respect to a particular problem using scientific methods such as collection of data, documenting critical information, analysis of data, and the establishment of facts in order to reach new conclusions.

Similarly, a basic research is an approach to research that's typically theoritical and it's aimed at developing a theory, searching for the truth or gain a better understanding about a phenomenon, subject, or basic laws on nature.

In this context, an example of basic research is the study of the composition of the atom.

An atom can be defined as the smallest unit comprising of matter that forms all chemical elements. Thus, atoms are basically the building blocks of matters and as such determines or defines the structure of a chemical element.

Generally, atoms are typically made up of three distinct particles and these are protons, neutrons and electrons.

5 0
2 years ago
A student creates a model that displays a cross-section of a metal wire wrapped in plastic insulation. Which statement best desc
artcher [175]

Cross-section of a metal wire wrapped in plastic insulation the metal wire is an element.

<h3>What is an element?</h3>

An element is a substance or material that cannot be affected by an external substance or cannot be broken down by any reaction.

Metal wire is serving as an element, it should not be easily broken or penetrated as an insulator.

Therefore, Cross-section of a metal wire wrapped in plastic insulation the metal wire is an element.

Learn more on element here,

brainly.com/question/18096867

7 0
2 years ago
0.25 mol of nitric acid is used to make a 0.10 M nitric acid solution. How many grams of solute was used?
Yanka [14]

Answer:

15.75 grams of HNO3 was used and dissolved in 2.5 liters of solvent, to make a 0.10 M solution

Explanation:

Step 1: Data given

Nitric acid = HNO3

Molar mass of H = 1.01 g/mol

Molar mass of N = 14.0 g/mol

Molar mass O = 16.0 g/mol

Number of moles nitric acid (HNO3) = 0.25 moles

Molairty = 0.10 M

Step 2: Calculate molar mass of nitric acid

Molar mass HNO3 = Molar mass H + molar mass N + molar mass (3*O)

Molar mass HNO3 = 1.01 + 14.0 + 3*16.0

Molar mass HNO3 = 63.01 g/mol

Step 3: Calculate mass of solute use

Mass HNO3 = moles HNO3 * molar mass HNO3

Mass HNO3 = 0.25 moles * 63.01 g/mol

Mass HNO3 = 15.75 grams

15.75 grams of HNO3 was used and dissolved in 2.5 liters of solvent, to make a 0.10 M solution

7 0
3 years ago
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