Initially the balloon was 21 liters with 4.00 moles of hydrogen
Therefore 1 mole of hydrogen had 21/4 = 5.25 liters
Therefore; 1 mole of oxygen would still contain 5.25 liters
Hence; 2 moles of oxygen contain 5.25 × 2 = 10.5 liters
Thus; the total volume of the balloon will be;
21 +10.5 = 31.5 liters
Answer:
0
Explanation:
If you mix NH3 and H2O the reaction is NH3 + H2O → NH4OH not NH3OH.
Te equation, like that is balanced. There is 1 N, 5H and 1 O in the reactives and 1 N, 5 H and 1 O so you have the same number of elements in the reactives and products, thus it's balanced and you don't need to do anything
This type of questions is relationed with REDOX balanced
Answer:
H₂O Gained Electron.
H₂O is <span>Bronsted-Lowry Base.
Explanation:
Due to amphoteric nature of water it can act as acid when reacted with strong base, also it can act as base when reacted with strong acid.
In given statement water is treated with strong acid hence it is acting as Bronsted-Lowery Base, as it accepting H</span>⁺. So those species which accepts proton are called as Bronsted-Lowry Base and those which donated proton are called as <span>Bronsted-Lowry Acid.
</span>
H₂O + H⁺ → H₃O⁺
If we are working in a coordinate plane where the endpoints has the coordinates (x1,y1) and (x2,y2) then the midpoint coordinates is found by using the following formula:
midpoint=(x1+x22,y1+y22)
T<span>his is a straightforward question related to the surface energy of the droplet. </span>
<span>You know the surface area of a sphere is 4π r² and its volume is (4/3) π r³. </span>
<span>With a diameter of 1.4 mm you have an original droplet with a radius of 0.7 mm so the surface area is roughly 6.16 mm² (0.00000616 m²) and the volume is roughly 1.438 mm³. </span>
<span>The total surface energy of the original droplet is 0.00000616 * 72 ~ 0.00044 mJ </span>
<span>The five smaller droplets need to have the same volume as the original. Therefore </span>
<span>5 V = 1.438 mm³ so the volume of one of the smaller spheres is 1.438/5 = 0.287 mm³. </span>
<span>Since this smaller volume still has the volume (4/3) π r³ then r = cube_root(0.287/(4/3) π) = cube_root(4.39) = 0.4 mm. </span>
<span>Each of the smaller droplets has a surface area of 4π r² = 2 mm² or 0.0000002 m². </span>
<span>The surface energy of the 5 smaller droplets is then 5 * 0.000002 * 72.0 = 0.00072 mJ </span>
<span>From this radius the surface energy of all smaller droplets is 0.00072 and the difference in energy is 0.00072- 0.00044 mJ = 0.00028 mJ. </span>
<span>Therefore you need roughly 0.00028 mJ or 0.28 µJ of energy to change a spherical droplet of water of diameter 1.4 mm into 5 identical smaller droplets. </span>