Answer:
When a solid changes into a gas, it is called sublimation.
Explanation:
Explanation:
The given data is as follows.
Mass of ice dropped = 325 g
Initial temperature =
= (30 + 273) K = 303 K
Final temperature =
= (0 + 273) K = 273 K
Now, using density of water calculate the mass of ice as follows.

= 500 g
As the relation between heat energy, specific heat and change in temperature is as follows.
Q = 
= 
= 62750 J
Also, relation between heat energy and latent heat of fusion is as follows.
Q = m L
= 
= 108300 J
Therefore, we require
heat but we have 40774.95 J.
So, 
=
= 188.4 g
Hence, the mass of ice = 325 g - 188.4 g
= 137 g
Therefore, we can conclude that 137 g of ice will still be present when the contents of the pitcher reach a final temperature.
Answer: I think its 32 I'm not sure
Explanation:
Answer:
700 calories
Explanation:
Using the formula below:
Q = m × c × ∆T
Where;
Q = amount of heat required (calories)
m = mass of substance (g)
c = specific heat of substance (cal/g°C)
∆T = change in temperature (°C)
According to this question, the following information was provided;
Q = ?
m = 20g
c = 1.0 cal/g °C
∆T = 40°C - 5°C = 35°C
Using the formula; Q = m × c × ∆T
Q = 20 × 1 × 35
Q = 700 calories
Hence, 700 cal of heat energy is needed to raise 20 g of H2O from 5°C to 40°C.
Answer:
104,000 has 3 significant figure.
Explanation:
This is because all non-zero digits are significant and zeros in between non-zero digits are significant.