PLSS ANSWERRRR

A container is filled with a mixture of gases:

strojnjashka [21]

Answer:

The partial pressure of chlorine gas in the mixture is 1.55 atm.

Explanation:

Partial pressure of oxygen gas = $p_1=1.0 atm$

Partial pressure of nitrogen gas = $p_2=0.75 atm$

Partial pressure of chlorine gas = $p_3=?$

Total pressure of the mixture of gases = P = 3.30 atm

Using Dalton's law of partial pressure:

$P=p_1+p_2+p_3$

$3.30 atm=1.0 atm+ 0.75 atm+p_3$

$p_3=3.30atm - (1.0 atm+ 0.75 atm)=1.55 atm$

The partial pressure of chlorine gas in the mixture is 1.55 atm.

8 0

3 years ago

In a 66.0-g aqueous solution of methanol, CH 4 O , CH4O, the mole fraction of methanol is 0.300. 0.300. What is the mass of each

Mumz [18]

Answer:

The solution is composed by 37.5 g of water and 28.5 g of methanol.

Explanation:

Total mass = 66 g

Mole fraction methanol: 0.3

Sum of mole fraction = 1

Therefore, mole fraction of water = 0.7

Let's find out the mass of each component by this two equations:

Methanol mass + Water mass = 66 g

Water mass = 66g - Methanol mass

Methanol mass = 66g - water mass

water mass / 18 g/mol = moles of water

methanol mass / 32 g/mol = moles of methanol

moles of water / total moles = 0.7

moles of methanol / total moles = 0.3

water mass / 18 g/mol / (water mass / 18 g/mol) + (methanol mass / 32 g/mol) = 0.7 ; let's replace methanol mass, as (66 - water mass)

water mass / 18 g/mol / (water mass / 18 g/mol) + (66 - water mass / 32 g/mol) = 0.7 → The unknown is water mass (X)

X / 18 / ( (X / 18) + ((66-X) / 32)) = 0.7

(X / 18) + ((66-X) / 32) = (16X + 594 - 9X)/288

X / 18 / (16X + 594 - 9X)/288 = 0.7

X/18 = 0.7 . ( (7X + 594 ) / 288)

X / 18 = 7/2880 ( 7X + 594)

X = 7/2880 ( 7X + 594) 18

X = 7/160 (7X + 594)

X = 49/160X + 2079/80

X - 49/160X = 2079/80

111/160X = 2079/80

X = 2079/80 . 160/111 = 37.5 g → mass of water

Therefore, mass of methanol → 66 g - 37.4 g = 28.5 g

7 0

3 years ago

How many grams of sodium chloride decompose to yield 15 grams of chlorine gas?

defon

Answer:

24.6g of NaCl

Explanation:

Expression of the reaction:

2NaCl → 2Na + Cl₂

Given parameters:

Mass of Cl₂ = 15g

Unknown:

Mass of NaCl = ?

Solution:

To solve this problem, we have to use mole relationships.

Find the number of moles of the mass of the given specie;

Number of moles = $\frac{mass}{molar mass}$

Molar mass of Cl₂ = 2(35.5) = 71g/mol

Number of moles = $\frac{15}{71}$ = 0.21mole

Now;

From the balanced reaction equation;

1 mole of Cl₂ is produced from 2 moles of NaCl;

0.21 mole of Cl₂ will be produced from 0.21 x 2 = 0.42mole of NaCl

So,

Mass of NaCl = number of moles x molar mass

Molar mass of NaCl = 23 + 35.5 = 58.5g/mol

Mass of NaCl = 0.42 x 58.5 = 24.6g of NaCl

8 0

3 years ago

I need help with this

ipn [44]

Can’t see it properly:(

6 0

3 years ago

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How many molecules are in 3 moles of CO2?

Alenkinab [10]

Answer:

Explanation:

The number of molecules can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 3 × 6.02 × 10²³

We have the final answer as

Hope this helps you

3 0

3 years ago

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