1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elanso [62]
4 years ago
7

Physical properties are those which can be measured or observed without changing the __________.

Physics
1 answer:
schepotkina [342]4 years ago
7 0

Answer:

Physical properties are those which can be measured or observed without changing the substance.

Explanation:

Physical properties are properties that can be measured or observed without changing the chemical nature of the substance. Some examples of physical properties are: color (intensive) density (intensive)

<u><em>Answer is B. Substance</em></u>

<u><em>Hope that helps</em></u>

You might be interested in
Hello I want to ask questions about physics
jek_recluse [69]

Answer:

tell ke first ,what will happen in zero gravity?

5 0
3 years ago
Read 2 more answers
9. If the musician hit the drum on a stage, how would the sound wave behave differently if he hit it the drum if the drum were s
egoroff_w [7]
I think it would be yes because the drum is submerged in water and the water would slow the sound waves, making the sound softer. Right?
4 0
3 years ago
A rocket starting from its launch pad is subjected to a uniform acceleration of 100 meters/second2. Determine the time needed to
gizmo_the_mogwai [7]

Answer:

10s

Explanation:

Acceleration is a measure of a rate of change of velocity, or in other words, a measure of how quickly the velocity is changing.

If acceleration is constant, then the velocity is changing by a constant amount.

With an acceleration of 100 m/s^2, starting from the launching pad (and thus, an initial velocity of zero), we can calculate how long it will take to reach a final velocity of 1000m/s with the following formula:

v=at+v_o where "v" is the final velocity at some later time "t", "a" is the constant acceleration, and "v" sub-zero is the initial velocity.

v=at+v_o

(1000\text{ [m/s]})=(100 \text{ } [\text{m/s}^2] )t+(0\text{ [m/s]})

1000\text{ [m/s]}=100 \text{ } [\text{m/s}^2] *t

\dfrac{1000\text{ [m/s]}}{100 \text{ } [\text{m/s}^2]}=\dfrac{100 \text{ } [\text{m/s}^2] *t}{100 \text{ } [\text{m/s}^2]}

10\text{ [s]}=t

So, it will take 10 seconds for the rocket to reach 1000m/s when starting from the launching pad, with a constant velocity of 100m/s^2.

<u>Verification:</u>

In this situation, it is quick to verify that 10 seconds is correct by looking at what the velocities will be each second.

Recognizing that the acceleration is a=\dfrac{100 [\frac{m}{s}]}{1[s]}, the velocity increases by 100 units [m/s] every second.

At time 0[s], the velocity is 0[m/s]

At time 1[s], the velocity is 100[m/s]

At time 2[s], the velocity is 200[m/s]

At time 3[s], the velocity is 300[m/s]

At time 4[s], the velocity is 400[m/s]

At time 5[s], the velocity is 500[m/s]

At time 6[s], the velocity is 600[m/s]

At time 7[s], the velocity is 700[m/s]

At time 8[s], the velocity is 800[m/s]

At time 9[s], the velocity is 900[m/s]

At time 10[s], the velocity is 1000[m/s]

So, indeed, after 10 seconds, the velocity reaches 1000 m/s

5 0
2 years ago
An apparatus similar to the one used in lab uses an oscillating motor at one end to vibrate a long rope with frequency f = 40 Hz
Mice21 [21]

Answer:

The displacement in t = 0,  

y (0) = - 0.18 m

Explanation:

Given f = 40 Hz , A = 0.25m , μ = 0.02 kg / m, T = 20.48 N

v = √ T / μ

v = √20.48 N / 0.02 kg /m = 32 m/s

λ = v / f

λ = 32 m/s / 40 Hz = 0.8

K = 2 π / λ

K = 2π / 0.8 = 7.854

φ = X * 360 / λ

φ = 0.5 * 360 / 0.8 = 225 °

Using the model of y' displacement

y (t) = A* sin ( w * t - φ )

When t = 0

y (0) = 0.25 m *sin ( w*(0) - 225 )

y (0) = 0.25 * -0.707

y (0) = - 0.18 m

5 0
4 years ago
What is the frictional force between a box and the floor it is being pulled across if, the kinetic coefficient of friction is 0.
Artyom0805 [142]

If the pulling is done parallel to the floor with constant velocity, then the box is in equilibrium. In particular, the weight and normal force cancel, so that

<em>n</em> = 38 N

The friction force is proportional to the normal force by a factor of 0.27, so that

<em>f</em> = 0.27 (38 N) ≈ 10.3 N

and so the answer is D.

8 0
3 years ago
Other questions:
  • Can u answer 4 and 5 for me
    11·1 answer
  • A 52-kg bike is moving along a smooth road at a constant velocity of 8.4 m/s. What is the net force acting on the bike
    15·1 answer
  • Could someone help me eliminate some of these answer choices?
    9·2 answers
  • How could winds influence the temperature
    15·1 answer
  • 1. While driving to Palm Desert you notice that some of the windmills near the freeway are spinning 20 times per minute. The len
    6·1 answer
  • 5 points
    13·1 answer
  • Which statement describes why energy is released in a nuclear fission reaction based on mass-energy equivalence?
    14·1 answer
  • a net force of 1,800 N is applied to a boat causing it to accelerate at 1.5 m/s^2. what is the mass of the boat?
    7·1 answer
  • Which of the following statements is correct about air temperature?
    15·2 answers
  • A large stone block is to be part of a harbour wall. The block is supported beneath the surface of the sea by a cable from a cra
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!