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3 years ago

What is the primary force that helps suspension bridges use cables to hold their spans up?

Physics

2 answers:

Wittaler [7]3 years ago

7 0

Answer:

a) Tension Force

Explanation:

Since the platform suspended by the strings so here weight of the platform is counter-balanced by the force due to strings.

Here all the molecules of string has tendency to connect with each other so that the internal force between the molecules will help them to bound with each other.

Since we know that this force between the molecules are electromagnetic force due to electron sharing between each other

So this force is known as tension force between the molecules.

So here correct answer force the suspension bridges, cables will exert internal tensile force to counter-balance the weight of the platform.

So correct answer will be

Tension force

Whitepunk [10]3 years ago

3 0

Hello There!

If i remember correctly, it is tension force.

Hope This Helps You!
Good Luck :)

- Hannah ❤

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In which layer of Earth’s interior does convection occur?

Tresset [83]

<u>Answer: </u>

Earth convection occurs at the mantle layer

<u>Explanation: </u>

The movement of less dense material above the more dense material is called as convection. The mantle is the layer that lies between the core and the crust of the earth. The mantle is composed of rocks containing silicon, magnesium, oxygen, aluminium, iron and other minerals.

The heat energy of the core is transmitted to the rock in the lower mantle. This makes the rock with less temperature that lies in upper mantle to move down slowly. Now the rocks that are pushed up is eventually cooled and again pushed down by the hotter rock from the lower mantle. This is called as convection in earth’s mantle .

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3 years ago

Read 2 more answers

Buoyant force acts in the opposite direction as the force of

Natalka [10]

Buoyant force acts in the opposite direction as the force of

Gravity

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3 years ago

I need help in my physics class and show me how it’s done

Korolek [52]

If we have the angle and magnitude of a vector A we can find its Cartesian components using the following formula

$A_x = |A|cos(\alpha)\\\\A_y = |A|sin(\alpha)$

Where | A | is the magnitude of the vector and $\alpha$ is the angle that it forms with the x axis in the opposite direction to the hands of the clock.

In this problem we know the value of Ax and Ay and we need the angle $\alpha$ .

Vector A is in the 4th quadrant

So:

$A_x = 6\\\\A_y = -6.5$

So:

$|A| = \sqrt{6^2 + (-6.5)^2}\\\\|A| = 8.846$

So:

$Ay = -6.5 = 8.846cos(\alpha)\\\\sin(\alpha) = \frac{-6.5}{8.846}\\\\sin(\alpha) = -0.7348\\\\\alpha = sin^{- 1}(- 0.7348)$

$\alpha$ = -47.28 ° +360° = 313 °

$\alpha$ = 313 °

Option 4.

4 0

3 years ago

a race car accelerates uniformly from 18.5 m/s to 46.1m/s in 2.47 seconds detrrmine the acceleration of the car and distance tra

LenaWriter [7]

Because acceleration is constant, the acceleration of the car at any time is the same as its average acceleration over the duration. So

$a=\dfrac{\Delta v}{\Delta t}=\dfrac{46.1\,\frac{\mathrm m}{\mathrm s}-18.5\,\frac{\mathrm m}{\mathrm s}}{2.47\,\mathrm s}=11.2\,\dfrac{\mathrm m}{\mathrm s^2}$

Now, we have that

${v_f}^2-{v_0}^2=2a\Delta x$

so we end up with a distance traveled of

$\left(46.1\,\dfrac{\mathrm m}{\mathrm s}\right)^2-\left(18.5\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(11.2\,\dfrac{\mathrm m}{\mathrm s^2}\right)\Delta x$