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Anika [276]
3 years ago
14

Tritium, the 3H atom, consists of a nucleus of one proton and two neutrons with a single electron. It is unstable and decays via

beta emission to singly ionized helium, 3 He , consisting of a nucleus of two protons and one neutron with a single electron. This decay takes place instantaneously and thus there occurs a sudden doubling of the Coulomb interaction between the atomic electron and the nucleus. If the tritium atom is in its ground state when it decays, determine the probability that the 3He atom is in its ground state immediately after the decay.
Required:
Determine the probability that the 3H^+ atom is in its ground state immediately after decay.
Physics
1 answer:
nika2105 [10]3 years ago
5 0

Answer: hello your question is poorly written attached below is the complete question

P(  ³₂He₊ )  at ground state = 1

Explanation:

<u>Determine the probability that the  3He atom is in its ground state after decay</u>

From the attached solution the coulomb interaction of ( ³₂He)  is double that of H³ . given that coulomb interaction is attractive ( -ve ) this will make  the product to become more stable hence the product ( ³₂He₊ ) will be gotten at the ground state

i.e. P(  ³₂He₊ )  at ground state = 1

attached below is a detailed solution

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3 years ago
The position of a car at time t is given by the function p(t)=t2 2t−4. What is the velocity when p(t)=11? assume t≥0
AysviL [449]

The velocity when function p(t)=11 is 8 .

According to the question

The position of a car at time t  represented by function :

p(t)=t^{2} +2t-4

Now,

When  function p(t) = 11 , t will be

p(t)=t^{2} +2t-4

11 = t²+2t-4

0 = t² + 2t - 15

or

t² +2t-15 = 0

t² +(5-3)t-15 = 0

t² +5t-3t-15 = 0

t(t+5)-3(t+5) = 0

(t-3)(t+5) = 0  

t = 3 , -5  

as t cannot be -ve as given ( t≥0)

so,

t = 3

Now,

the velocity when p(t)=11

As we know velocity = \frac{position}{time}

therefore to get the value of velocity from  function p(t)

we have to differentiate the function with respect to time

\frac{d(p(t))}{dt} =\frac{d}{dt} (t^{2} +2t-4)

v(t) = 2t + 2  

where v(t) = velocity at that time

as t = 3 for  p(t)=11  

so ,

v(t) = 2t + 2  

v(t) = 2*3 + 2  

v(t) = 8

Hence, the velocity when function p(t)=11 is 8 .

To know  more about function here:

brainly.com/question/12431044

#SPJ4

4 0
2 years ago
An iron sphere of radius 0.18m has mass 190 kg. Calculate the density of the iron
Slav-nsk [51]
  • radius=r=0.18m

Volume:-

\\ \sf\rightarrowtail \dfrac{4}{3}\pi r^3

\\ \sf\rightarrowtail \dfrac{4}{3}\pi (0.18)^3

\\ \sf\rightarrowtail \dfrac{4}{3}\pi (0.005832)

\\ \sf\rightarrowtail 0.024m^3

  • Mass=190kg

Density:-

\\ \sf\rightarrowtail \dfrac{Mass}{Volume}

\\ \sf\rightarrowtail \dfrac{190}{0.024}

\\ \sf\rightarrowtail 7916.67kg/m^3

8 0
2 years ago
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