The angle that the water surface make with the horizontal is 0.527°.
<h3>How to calculate the angles?</h3>
The water vapor moves at speed. Therefore,
v = 2πr/T = (2 × π × 0.120)/7.25
= 0.104m/s
Also, the top layer of water deals a downward force if gravity which will be:
= mv²/r = 0.104/0.12 = 0.0901
There, the angle will be:
= tan(0.0901/9.8)
= 0.527°
In this case, the angle that the water surface make with the horizontal is 0.527°.
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The two aircrafts are skidded for 14.9 s.
To find the answer, we need to know about the Newton's equation of motion.
<h3>What is the Newton's equation that relates velocity, distance, acceleration and time?</h3>
As per Newton's equation of motion
- V²-U²= 2aS
- V= U+at
- V= final velocity, U = initial velocity, S = distance, a= acceleration, t= time
<h3>What's the acceleration of the aircrafts that skidded from 35 m/s after the collision for 112.1 m before achieving 15 m/s?</h3>
- Here, U = 35 m/s, V = 15m/s, S= 112.1 m
- So, 15²- 35²= 2a×112.1= 224.2a
=> a= -1000/224.2= -4.5 m/s²
<h3>What's the time taken to stop if these aircrafts are de-accelerated by 4.5 m/s² from 35m/s?</h3>
- Here, U = 35 m/s, V=15 m/s a= -4.5 m/s²
- 35= 15+(-4.5)t
=> t= 20/4.5 = 4.4 s
Thus, we can conclude that the two aircrafts are skidded for 4.4 s.
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Answer:
B. The object's volume
Explanation:
When an object is immersed in a fluid, it experiences an upward force which is called buoyant force. The magnitude of the buoyant force is given by:
where
is the density of the fluid in which the object is immersed
is the volume of the fluid displaced by the object
is the acceleration due to gravity
When the object is totally immersed in the fluid, corresponds to the volume of the object; when the object is only partially immersed, corresponds only to the volume of the part of the object immersed.
From the formula, we see that the greatest buoyant force is experienced by the object when it is fully immersed. Moreover, we see that the buoyant force depends only on one property of the object: its volume. Therefore, the correct choice is
B. The object's volume
First, let us derive our working equation. We all know that pressure is the force exerted on an area of space. In equation, that would be: P = F/A. From Newton's Law of Second Motion, force is equal to the product of mass and gravity: F = mg. So, we can substitute F to the first equation so that it becomes, P = mg/A. Now, pressure can also be determined as the force exerted by a fluid on an area. This fluid can be measure in terms of volume. Relating volume and mass, we use the parameter of density: ρ = m/V. Simplifying further in terms of height, Volume is the product of the cross-sectional area and the height. So, V = A*h. The working equation will then be derived to be:
P = ρgh
This type of pressure is called the hydrostatic pressure, the pressure exerted by the fluid over a known height. Next, we find the literature data of the density of seawater. From studies, seawater has a density ranging from 1,020 to 1,030 kg/m³. Let's just use 1,020 kg/m³. Substituting the values and making sure that the units are consistent:
P = (1,020 kg/m³)(9.81 m/s²)(11 km)*(1,000 m/1km)
P = 110,068,200 Pa or 110.07 MPa
