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3 years ago

This type of a boundry can be located at around 40 N latitude and 0 long titude

Physics

2 answers:

blondinia [14]3 years ago

8 0

Answer:

if there are no options then i would say the Atlantic oceans

if there are options let me know

elena-14-01-66 [18.8K]3 years ago

3 0

the fences around individual shops or homes in eastern Spain

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A spring with a spring constant of 120 J/m2 is fixed to a wall, free to oscillate. On the other end, a ball with a mass of 1500

Neporo4naja [7]

Answer:

A. 4.47 m/s

Explanation:

As the ball oscillates, it mechanical energy, aka the total kinetic and elastics energy stays the same. For the ball to be at maximum speed, its elastic energy i 0 and vice versa. When the ball is at rest, its kinetic energy is 0 and its elastic energy is at maximum at 50 cm, or 0.5 m

1500 g = 1.5 kg

$E_e = E_k$

$kx^2/2 = mv^2/2$

$120*0.5^2/2 = 1.5*v^2/2$

$15 = 0.75v^2$

$v^2 = 15 / 0.75 = 20$

$v = \sqrt{20} = 4.47 m/s$

5 0

4 years ago

On his way off to college, Russell drags his suitcase 19 m from the door of his house to the car at a constant speed with a hori

Mashcka [7]

Answer:

The work done on the suitcase is, W = 1691 J

Explanation:

Given data,

The force on the suitcase is, F = 89 N

The distance Russell dragged the suitcase, S = 19 m

The work done on the suitcase by Russell is equal to the work done on the suitcase to overcome the friction

The work done on the suitcase by Russell is given by the formula

W = F · S

Substituting the given values,

W = 89 N x 19 m

W = 1691 J

Hence, the work done on the suitcase is, W = 1691 J

8 0

4 years ago

A uniform electric field, with a magnitude of 370 N/C, is directed parallel to the positive x-axis. If the electric potential at

dem82 [27]

Answer:

$\Delta U = 0.2072 J$

Explanation:

Potential difference between two points in constant electric field is given by the formula

$\Delta V = E.\Delta x$

here we know that

$E = 370 N/C$

also we know that

$\Delta x = 2.1 - 1.9 = 0.2 m$

now we have

$\Delta V = 370 (0.2) = 74 V$

now change in potential energy is given as

$\Delta U = Q\Delta V$

$\Delta U = (2.80 \times 10^{-3})(74)$

$\Delta U = 0.2072 J$

3 0

4 years ago

When an object is placed just outside the focal length of a concave mirror, the image is

swat32

Answer:

O larger than the object and real

Explanation:

As we know by the formula of mirror

$\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}$

here we know that

$d_o = (f_o + x)$

so we have

$\frac{1}{d_i} = \frac{1}{f_o} - \frac{1}{f_o + x}$

so we have

$d_i = \frac{(f_o)(f_o + x)}{x}$

so magnification is given as

$M = -\frac{d_i}{d_o}$

$M = - \frac{f_o}{x}$

so here we have

$|M| > 1$

so image will be larger than object and real

8 0

3 years ago

Suppose that on a routine trip around the galaxy, your dog puts his head out of the spacecraft window (as dogs often do). The so

neonofarm [45]

Answer: Yes, the dog's head will burn

Explanation:Solar winds are strongly destructive magnetically charged high energy winds. Satellite communication on earth and the occasional geomagnetic storm near the poles are the major disruptive effects caused by solar winds on earth.

Since solar winds are streams of charged particles released from the upperparts of the Sun, called the "corona". This plasma mainly consists of electrons, protons and alpha particles with kinetic energy between 0.5 and 10 keV. Instilled within the solar-wind plasma is the interplanetary magnetic field.

If the dog holds it's breath the heat wave would burn it's head but not outrightly because the breath has ceased for some seconds and it can't absorb the much heat of the solar wind into it's nostrils. The effect of holding its breath would still be disastrous but not as the first case.

7 0

3 years ago