Answer:
vT = v0/3
Explanation:
The gravitational force on the satellite with speed v0 at distance R is F = GMm/R². This is also equal to the centripetal force on the satellite F' = m(v0)²/R
Since F = F0 = F'
GMm/R² = m(v0)²/R
GM = (v0)²R (1)
Also, he gravitational force on the satellite with speed vT at distance 3R is F1 = GMm/(3R)² = GMm/27R². This is also equal to the centripetal force on the satellite at 3R is F" = m(vT)²/3R
Since F1 = F'
GMm/27R² = m(vT)²/3R
GM = 27(vT)²R/3
GM = 9(vT)²R (2)
Equating (1) and (2),
(v0)²R = 9(vT)²R
dividing through by R, we have
9(vT)² = (v0)²
dividing through by 9, we have
(vT)² = (v0)²/9
taking square-root of both sides,
vT = v0/3
Answer:
420m
Explanation:
Given parameters:
Time = 5minutes
Average speed = 1.4m/s
Unknown:
Distance covered = ?
Solution:
Speed is the rate of change of distance with time.
Mathematically;
Speed =
Distance = speed x time
Insert the parameters and solve;
Convert the time to seconds;
1 minute = 60s
5 minute = 5 x 60 = 300s
So,
Insert the parameters and find the distance;
Distance = 300 x 1.4 = 420m
Based on what we know, we can confirm that the wave behavior being observed when light passes through media of different densities is refraction.
<h3>What is refraction?</h3>
This is a term used to explain the behavior of light as it moves through distinct mediums. This behavior includes a change in direction of the light due to its change in speed.
Therefore, the wave behavior being observed when light passes through media of different densities is refraction.
To learn more about light waves visit:
brainly.com/question/3004869?referrer=searchResults
The necessary light intensity of the disk if the disk has mass 3.89 g and radius 2.40 cm is 6.483 x 10^12cd.
<h3>Calculations and Parameters:</h3>
a. Given that:
- i= intensity of light
- m= mass of disk
- g= gravitational acceleration
- c= speed of light
- a= cross-sectional area of the disk
I = P/A
= Force x Speed/Area
Gravitational force, F= GM1M2/r^2
F= ma, F= mg
I= mg x c/q
That is,
i= mass x gravitational acceleration x speed/area
b.
Mass= 3.89g
Radius, r= 2.40cm
i=?
i= mg x c/a
Speed of light= 3.0 x 10^8 m/s
Area, a= /pi r^2
= 3.142 x (0.024)^2
= 3.142 x 0.000576
= 0.0018m^2.
i= 3.89 x 10 x 3.0 x 10^8/0.0018
i= 6.483 x 10^12cd.
c. Light has no mass, therefore, it lacks momentum and cannot exert pressure for propulsion of materials.
Read more about light intensity here:
brainly.com/question/11355584
C) at the bottom of the hill