Answer:
The answer is given below
Step-by-step explanation:
The loads in the circuit are continuous duty, so the circuit can only loaded to 80% of its current rating.
Calculate 80% current rating of the circuit breaker.
Icb = [ 80/100] (20 A)
= (O.8) (20 A )
= 16 A
Now we assume that the value of supply voltage is 120 V
Now we will calculate current flows via under water light which will be taken as Load 1
<em>Ii = </em>500 W/120 V
= 4.167 A
Current via the circulating pump which will be taken as Load 2 IS 8.5 A
<em>I = </em>load1 + load 2
<em> = 4.167 A + 8.5 A</em>
<em> = 12.67 A</em>
The total current in the circuit obtained which is less than the circuit breaker rating current. Therefore, the power can be operated for both the loads.
Answer:
2nd graph above the one you chose
Dont mind this its just to ask a question
Answer:
12
Step-by-step explanation:
(whole secant) x (external part) = (tangent)^2
PC * PA = PB^2
(PA+AC) * PA = PB^2
(4+32) * 4 = PB^2
36*4 = PB^2
144 = PB^2
Taking the square root of each side
sqrt(144) = sqrt(PB^2)
12= PB
