All categories

3 years ago

What conditions are necessary for heat to flow?

1 answer:

5 0

if it is heat flow through a metal, it would be necessary to have a conductor so that the electrons can flow through it (delocalised electrons).

In terms of radiation, it would require a good absorber of heat (e.g. a black surface) so that the thermal energy flows through on the surface area.

You might be interested in

Which terms both represent scalar quantities?

ELEN [110]

The answer should be B

3 0

3 years ago

A heat engine operating at steady state delivers a power output of 15.5 hp. The engine receives energy by heat transfer in the a

Anna007 [38]

Answer:

w_cycle = 13.68 KJ / cycle

Explanation:

Given:

- Steady power out-put W_out = 15.5 hp

- System executes 50 cycles/min

Find:

Determine the amount of work that is delivered during each cycle in kilo-joules

Solution:

- First we will convert the steady output into KW as follows:

W_out = 15.5 hp

The conversion factor is 1.36 KW per hp.

W_out = 15.5 [hp] * [KW] / 1.36 [hp]

W_out = 11.4 [KW] or [KJ/s]

- Given that there are 50 cycles in 60 sec. We will use direct proportionality to calculate the number of cycles per second:

50 cycles -----------> 60 s

x cycles -----------> 1 s

x = 50/60 = 0.8333 cycles /s

- Next we will compute the amount of work done per cycle:

w_cycle = W_out / x

w_cycle = 11.4 [KJ/s] * [s] / 0.8333 [cycles]

w_cycle = 13.68 KJ / cycle

7 0

3 years ago

A coating is being applied to reduce the reflectivity of a pane of glass to light with a wavelength of 522 nm incident near the

fredd [130]

Answer:

t = 94.91 nm

Explanation:

given,

wavelength of the light = 522 nm

refractive index of the material = 1.375

we know the equation

c = ν λ

where ν is the frequency of the wave

c is the speed of light

$\nu= \dfrac{c}{\nu\lambda}$

$\nu = \dfrac{3\times 10^8}{522 \times 10^{-9}}$

ν = 5.75 x 10¹⁴ Hz

the thickness of the coating will be calculated using

$t = \dfrac{\lambda}{4\mu_{material}}$

$t = \dfrac{522 \times 10^{-9}}{4\times 1.375}$

t = 94.91 nm

the thickness of the coating will be equal to t = 94.91 nm

7 0

3 years ago

What are the uses of evaporative salts?

Makovka662 [10]

<span>to preserve foods, dye fabric, and DE-ice roads i hopes this helps

</span>

4 0

3 years ago

an object with a mass of 2.4 kg has a force of 12.6 N applied to it. What is the resulting acceleration of the object? WITH PROO

Scorpion4ik [409]

Newton’s Law: F = MA
A = F/M (change equation)
12.6 N/ 2.4 kg = 5.25
Answer: acceleration is 5.25 m/s^2

3 0

3 years ago