a). Frequency = (4,000 rev/minute)·(1 minute/60 sec) = <em>66 and 2/3 rev/sec</em>
b). Period = 1 / frequency
Period = 1 / (66-2/3 rev/sec)
Period = 1/66-2/3 sec/rev
<em>Period = 0.015 sec/rev </em>
Answer:
313.6N
Explanation:
Given parameters;
Mass of the body = 50kg
Coefficient of friction = 0.64
Acceleration due to gravity = 9.81m/s²
Unknown:
Minimum force needed to move the body = ?
Solution:
To move this body, the minimum force must overcome the frictional force. So, the value of force that equals to that of the frictional force will set the body in motion.
Frictional force = Umg
U is the coefficient of friction
m is the mass
g is the acceleration due to gravity
Now insert the parameters and solve;
Frictional force = 0.64 x 50 x 9.8 = 313.6N
Answer:
Explanation:
We want to write the equation of displacement (vertical in this case) for accelerated motion, which is . If we take the upward direction as positive, assume it starts from rest and from the ground, and (the units are wrong in the text, if accelerates at that magnitude, it's an acceleration, in particular in ), then we have .
We want to know the time when , so we need to solve , for which we have:
This means it takes 4 seconds for a rocket accelerating at to reach a height of 192m.
Answer:
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You can identify by:
a. boiling point
c. density.