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Tasya [4]
4 years ago
8

Two boats leave a dock together . Each travels in a straight line . The angle between their courses measures 54° 10¢ . One boat

travels 36.2 km/hr and the other travels 45.6 km/hr. How far apart will they be after three hours
Physics
1 answer:
nata0808 [166]4 years ago
3 0

Answer:

218.93 km

Explanation:

\theta = Angle between the paths of the two boats = 54.10°

Distance = Speed × Time

Distance traveled by one boat = 36.2\times 3\ km

Distance traveled by other boat = 45.6\times 3\ km

From the triangle law of vectors we have

d=\sqrt{(36.2\times 3)^2+(45.6\times 3)^2+2\times 36.2\times 3\times 45.6\times 3\times cos54.10}\\\Rightarrow d=218.93\ km

The distance they will be apart after 3 hours is 218.93 km

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Introduction

Matter & Energy

Math Review

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Newton's 3rd Law Equation

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Although this law surrounds your actions everyday, often times you may not even realize its effects. To run forward, a cat pushes with its legs backward on the ground, and the ground pushes the cat forward. How do you swim? If you want to swim forwards, which way do you push on the water? Backwards, that’s right. As you push backwards on the water, the reactionary force, the water pushing you, propels you forward. How do you jump up in the air? You push down on the ground, and it’s the reactionary force of the ground pushing on you that accelerates you skyward!

As you can see, then, forces always come in pairs. These pairs are known as action-reaction pairs. What are the action-reaction force pairs for a girl kicking a soccer ball? The girl’s foot applies a force on the ball, and the ball applies an equal and opposite force on the girl’s foot.

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