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Tasya [4]
3 years ago
8

Two boats leave a dock together . Each travels in a straight line . The angle between their courses measures 54° 10¢ . One boat

travels 36.2 km/hr and the other travels 45.6 km/hr. How far apart will they be after three hours
Physics
1 answer:
nata0808 [166]3 years ago
3 0

Answer:

218.93 km

Explanation:

\theta = Angle between the paths of the two boats = 54.10°

Distance = Speed × Time

Distance traveled by one boat = 36.2\times 3\ km

Distance traveled by other boat = 45.6\times 3\ km

From the triangle law of vectors we have

d=\sqrt{(36.2\times 3)^2+(45.6\times 3)^2+2\times 36.2\times 3\times 45.6\times 3\times cos54.10}\\\Rightarrow d=218.93\ km

The distance they will be apart after 3 hours is 218.93 km

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