Do you have options to choose from? that would be a big help so I can answer ur question
Answer:
Q = 10.8 KJ
Explanation:
Given data:
Mass of Al= 100g
Initial temperature = 30°C
Final temperature = 150°C
Heat required = ?
Solution:
Specific heat of Al = 0.90 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 150°C - 30°C
ΔT = 120°C
Q = 100g×0.90 J/g.°C× 120°C
Q = 10800 J (10800j×1KJ/1000 j)
Q = 10.8 KJ
Hey there!:
Given, energy, E = 703 kJ/mol
λ = ?
We need to do conversion of kJ/mol to J
So, E = 703 kJ/mol*1000 J*kJ *1 mole / 6.023*10²³
= 1.17*10-18 J
We know formula,
E = h*C/ λ
So, λ = h*C / E
= ( 6.626*10-34 J.s ) * ( 3.0*10⁸ m.s⁻¹ ) / ( 1.17*10⁻¹⁸ J )
= 1.70*10⁻⁷ m
So, 1 m = 1*10⁹ nm
So, 1.70*10⁻⁷ m = ?
= 170 nm
Hope that helps!
Answer:
The second option
Explanation:
Check
2×2Fe = 4Fe. Both sides have 4 Fe's
2x3 O = 3x2 O Both sides have 6 O's
3x1C = 3 C Both sides have 3 C's
