A. cesium. bacause as the elements go down a group of the atoms, the sizes of the atom will increase . we know that tge tendency to lose an electron is based on the sizes of the atoms of group 1.
Is a solid? has strong intermolecular forces?
Answer: No
Explanation:
- Law of definite proportions is a case from the Law of conservation of energy (matter) which states that "mass can neither be created nor destroyed, but changed from one form to another."
- Adding coefficients to a chemical equation confirms that there is the same number of atoms on both sides of a reaction; therefore, matter has not been created or destroyed but reorganized to give new substrates.
Example : 2 Mg + O2 → 2 MgO
In the balanced equation above, 2 moles of Mg reacts with 1 mole of O2 to produce 2 moles of MgO.
mass of 2 moles of Mg = 24×2= 48 grams
mass of 1 mole of O2 = 16+16 = 32 grams
total mass of reactants = 48 + 32 = 80 grams
mass of 2 moles of MgO = (24+16) ×2 = 80 grams
total mass of products = 80 grams
It is clear that the number of grams of matter before and after the reaction is the same and equals to 80 grams, so obeys the law of definite proportions..
Answer:
Aspartic acid may be considered hydrophobic at physiological.
For a (unbalanced) reaction: NaOH +CO2-Na2CO3 + H2O, the moles of NaOH and moles of each product are formed are mathematically given as
a) Moles of NaOH =44.05
b) Moles of Na2CO3=21.0
<h3>What is the moles of NaOH and what moles of each product are formed?</h3>
Generally, the equation for the Chemical reaction is mathematically given as
2 NaOH(aq)+ CO2(g)------> Na2CO3(aq)+ H2O(l)
Therefore
Moles of CO2= 925/44
Moles of CO2=21.0
Hence
Moles of NaOH = 2 x Moles of CO2
Moles of NaOH = 2x925/44
Moles of NaOH =44.05
In conclusion
Moles of Na2CO3 925/44
Moles of Na2CO3=21.0
And
Moles of H2O= 925/44
Moles of H2O= 21.0
Read more about Chemical reaction
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