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ella [17]
2 years ago
10

When hcl(aq) and naoh(aq) are mixed in a beaker, the beaker feels warm to the touch. what is known about the enthalpy of this re

action? view available hint(s) when and are mixed in a beaker, the beaker feels warm to the touch. what is known about the enthalpy of this reaction? heat is absorbed from the surroundings. δh is positive. the reaction is exothermic. the reaction is endothermic?
Chemistry
1 answer:
Nady [450]2 years ago
5 0

The balanced chemical equation representing the neutralization reaction of hydrochloric acid (HCl) and sodium hydroxide (NaOH),

HCl (aq) + NaOH(aq) ---> NaCl(aq) + H_{2}O(l) + Heat

This reaction is exothermic that is it proceeds by the release of heat energy. This heat energy is lost to the surroundings. This is the reason for the warming up of the beaker where the reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) takes place. The enthalpy of such reaction will be negative as the reaction is exothermic.

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Help and show work please
olya-2409 [2.1K]
ANWERS ~
We know that :
1 cal (th) = 4.184 J
1 J = 0.2390057361 cal (th) , so :

•55.2 j to cal > 13.193116635 cal
•110 call > 460.24 joule
•65 kj > divide the energy value by 4.184
= 15.535 kilocalories calorie (IT)
——————
Converting form C to F > (F-32)*5/9Understand it better if we have Fahrenheit just add to the equation mentioned to find Celsius.
+to find F to C> (9/5*C)+32

•425 Fahrenheit = (425- 32) × 5/9 =218.33333333 Celsius

•1935 C = 3515 F
———————————-
Converting Celsius to kelvin,We know that :
K = C + 273.15
C = K - 273.15
And from F to K=9/5(F+459.67)
And K to F =(9/5 *k)-459.67
•39.4 Celsius = 312.55 kelvin
•337 Fahrenheit = (337+ 459.67) × 5/9 =442.594 kelvin





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For the options:

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<em />

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using cross multiplication:

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1.0 mol occupies → 22.4 L.

??? mol occupies → 2.24 L.

<em>The no. of moles of (2.24 L) Xe </em>= (1.0 mol)(2.24 L)/(22.4 L) = <em>0.1 mol.</em>

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