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diamong [38]
4 years ago
13

A body is suspended from the ceiling with two wires that make an angle of 40° with the ceiling. The weight of the body is 150N.

What is the tension in each wire?
Physics
1 answer:
Maru [420]4 years ago
8 0
The aid of a free-body diagram is essential for solving this mechanics problem. The summation of horizontal and vertical forces in the system must be equal to zero since the body is in equilibrium. 

Summation of x-forces:

T*cos(40)-T*cos(40) = 0

y forces:

2T*sin(40) - 150 = 0

T = 150/2*sin(40) = 100.66 N

Therefore, the tension in each wire would be 100.66 Newtons.

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A spring with spring constant 15 N/m hangs from the ceiling. A ball is attached to the spring and allowed to come to rest. It is
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Answer:

a

   m  = 0.169 \ kg

b

  |v_{max} |=  0.5653 \ m/s

Explanation:

From the question we are told that

    The  spring constant is  k =  14 \ N/m

     The  maximum extension of the spring is  A =  6.0 \ cm  =  0.06 \ m

     The number of oscillation is  n  =  30

      The  time taken is  t  =  20 \ s

Generally the the angular speed of this oscillations is mathematically represented as

           w = \frac{2 \pi}{T}

where T is the period which is mathematically represented as

     T  =  \frac{t}{n}

substituting values

     T  =  \frac{20}{30 }

     T  = 0.667 \ s

Thus  

       w = \frac{2 * 3.142 }{ 0.667}

       w =  9.421 \ rad/s

this angular speed can also be represented mathematically as

       w =  \sqrt{\frac{k}{m} }

=>   m  =\frac{k }{w^2}

substituting values

      m  =\frac{ 15 }{(9.421)^2}

      m  = 0.169 \ kg

In SHM (simple harmonic motion )the equation for velocity is  mathematically represented as

        v =  - Awsin (wt)

The  velocity is maximum when  wt = \(90^o) \ or \ 1.5708\ rad

     v_{max} = -  A* w

=>   |v_{max} |=  A* w

=>    |v_{max} |=   0.06 * 9.421

=>   |v_{max} |=  0.5653 \ m/s

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