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diamong [38]
4 years ago
13

A body is suspended from the ceiling with two wires that make an angle of 40° with the ceiling. The weight of the body is 150N.

What is the tension in each wire?
Physics
1 answer:
Maru [420]4 years ago
8 0
The aid of a free-body diagram is essential for solving this mechanics problem. The summation of horizontal and vertical forces in the system must be equal to zero since the body is in equilibrium. 

Summation of x-forces:

T*cos(40)-T*cos(40) = 0

y forces:

2T*sin(40) - 150 = 0

T = 150/2*sin(40) = 100.66 N

Therefore, the tension in each wire would be 100.66 Newtons.

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If the small piston has an area of .004 square
denpristay [2]

The magnitude of the pressure : P = 56,250 N/m

<h3>Further explanation</h3>

Given

Area of 0.004 m²

Force 225 N

Required

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Which has a total mass of 1612 kg. If she accelerates from rest to a speed of 12.87 m/s in 3.47 s, what is the minimum power req
blondinia [14]

Answer:

76969.29 W

Explanation:

Applying,

P = F×v............. Equation 1

Where P = Power, F = force, v = velocity

But,

F = ma.......... Equation 2

Where m = mass, a = acceleration

Also,

a = (v-u)/t......... Equation 3

Given: u = 0 m/s ( from rest), v = 12.87 m/s, t = 3.47 s

Substitute these values into equation 3

a = (12.87-0)/3.47

a = 3.71 m/s²

Also Given: m = 1612 kg

Substitute into equation 2

F = 1612(3.71)

F = 5980.52 N.

Finally,

Substitute into equation 1

P = 5980.52×12.87

P = 76969.29 W

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