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zlopas [31]
3 years ago
8

PLEASE HELP!!! GIVING BRAINLIEST!! ill also answer questions that you have posted if you answer these correctly!!!! (47pts)

Physics
2 answers:
Reptile [31]3 years ago
5 0

Answer:

can I have points, i don't have any money

Airida [17]3 years ago
4 0

gave you earlier :) Check

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Sean, whose mass is 60 kg, is riding on a 5.0 kg sled initially traveling at 8.0 m/s. He brakes the sled with a constant force,
alexgriva [62]

Answer:

<h3>130N</h3>

Explanation:

according to Newtons second law;

F = ma

F = m(v-u)/t

m is the mass = 60+5 = 65kg

v is the final velocity = 0m/s

initial velocity = 8m/s

time t = 4.0s

F = 65(8)/4

F = 65*2

F = 130N

Hence he applied a force of 130N

7 0
3 years ago
How do I impact the highway transportation system?
madreJ [45]

Answer:

Commercial vehicles

Explanation:

8 0
4 years ago
Is the refraction different entering medium that has a higher index of refraction compared to entering amedium that has a lower
oee [108]

Answer:

Yes

Explanation:

The speed of light when it travels through glass, diamond, etc, the light travels at different speed from the speed of light. Speed of the light in material is related to the index of refraction.

The change in speed which occurs when the light passes from one medium to the another is responsible for bending of the light which is called as refraction.

<u>When the light goes into a medium with the higher index of the refraction, light bends towards normal. Conversely, if the light traveling goes from higher refractive index to lower refractive index, it will bend away from the normal. </u>

<u>Hence, the refraction is different in both the scenario.</u>

6 0
3 years ago
A particle executes simple harmonic motion with an amplitude of 2.00 cm. At what positions does its speed equal one fourth of it
White raven [17]

Answer:

The positions are  0.0194 m  and - 0.0194 m.

Explanation:

Given;

amplitude of the simple harmonic motion, A = 2.0 cm = 0.02 m

speed of simple harmonic motion is given as;

v = \omega \sqrt{A^2-x^2}

the maximum speed of the simple harmonic motion is given as;

v_{max} = \omega A

when the speed equal one fourth of its maximum speed

v =\frac{v_{max}}{4}

\omega\sqrt{A^2-x^2} = \frac{\omega A}{4} \\\\\sqrt{A^2-x^2}= \frac{A}{4}\\\\A^2-x^2 = \frac{A^2}{16} \\\\x^2 = A^2 - \frac{A^2}{16} \\\\x^2 = \frac{16A^2 - A^2}{16} \\\\x^2 = \frac{15A^2}{16} \\\\x= \sqrt{\frac{15A^2}{16} } \\\\x = \sqrt{\frac{15(0.02)^2}{16} }\\\\x = 0.0194 \ m  \ \ or\  - 0.0194  \ m

Thus, the positions are  0.0194 m and - 0.0194 m.

8 0
3 years ago
Which of the following corn pests causes galls to develop on the plant?
Vlad1618 [11]

Answer:

The answer is Smut.

Explanation:

5 0
3 years ago
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