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UkoKoshka [18]
3 years ago
7

A small electric motor produces a force of 5 N that moves a remote-control car 5 m every second. How much power does the motor p

roduce? Give your answer in watts and horsepower.
Physics
2 answers:
PolarNik [594]3 years ago
5 0

Answer:

25 W

or

0.0335 hp

Explanation:

Power: This can be defined as the rate at which work is done. The S.I ubit of power is Watt(W).

The expression for Power in terms of force and velocity is given as,

P = F×V.................. Equation 1

Where P = Power, F = force of the electric motor, V = Velocity of electric motor

Given: F = 5 N, V = 5 m/s.

Substitute into equation 2

P = 5×5

P = 25 W.

P = 25 W

or

P = 25(0.00134) horse power

P = 0.0335 hp

Hence the motor produce a power of 25 W or 0.0335 hp

kati45 [8]3 years ago
4 0

Answer:

Explanation:

Given:

Force, f = 5 N

Velocity, v = 5 m/s

Power, p = energy/time

Energy = mass × acceleration × distance

Poer, p = force × velocity

= 5 × 5

= 25 W.

Note 1 watt = 0.00134 horsepower

But 25 watt,

0.00134 hp/1 watt × 25 watt

= 0.0335 hp.

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Angel Falls is 3,230 feet, which is the tallest waterfall in the world.
Hope this helps!
Happy studying,
~Mistermistyeyed.
5 0
3 years ago
Razona si, en las experiencias de Faraday, el efecto producido moviendo el circuito será el mismo que el producido moviendo el i
const2013 [10]

Answer:

moving the circuit or the magnet gives the same result

Explanation:

The faraday effect establishes that the temporal variation of imaginative flow produces an electric potential

          fem = \frac{d \phi }{dt}dfi / dt

the magnetic flux is

         Ф = B. A = B A cos θ

suppose for simplicity that the angle is zero so cos 0 = 1

         Φ = B A

By analyzing this expression, the change in magnetic flux can converge while keeping the magnetic field fixed and varying the electric field or keeping the electric field fixed and varying the magnetic field.

Consequently moving the circuit or the magnet gives the same result

5 0
3 years ago
An electron enters a region with a speed of 5×10^6m/s and is slowed down at the rate of 1.25×10^-4m/s². How far does the electro
Mashutka [201]

1) The distance travelled by the electron is 1\cdot 10^{17} m

2) The time taken is 4.0\cdot 10^{10}s

Explanation:

1)

The electron in this problem is moving by uniformly accelerated motion (constant acceleration), so we can use the following suvat equation

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance travelled

For the electron in this problem,

u=5\cdot 10^6 m/s is the initial velocity

v = 0 is the final velocity (it comes to a stop)

a=-1.25\cdot 10^{-4} m/s^2 is the acceleration

Solving for s, we find the distance travelled:

s=\frac{v^2-u^2}{2a}=\frac{0-(5\cdot 10^6)^2}{2(-1.25\cdot 10^{-4})}=1\cdot 10^{17} m

2)

The total time taken for the electron in its motion can also be found by using another suvat equation:

v=u+at

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

Here we have

u=5\cdot 10^6 m/s

v = 0

a=-1.25\cdot 10^{-4} m/s^2

And solving for t, we find the time taken:

t=\frac{v-u}{a}=\frac{0-5\cdot 10^6}{-1.25\cdot 10^{-4}}=4.0\cdot 10^{10}s

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

7 0
3 years ago
A sound wave with a frequency of 300 hertz is traveling through a medium at a speed of 320 meters/second. What is its wavelength
Alekssandra [29.7K]
<span>320=300wavelenght=1.06 m

</span>
5 0
3 years ago
Read 2 more answers
30 POINTS!!! I need help ASAP, if someone comments just for points, or is incorrect just for points I will report! Please help!!
Anika [276]

Answer:

1.) answer B

2.) answer D

3.) answer A

Explanation:

In all of these problems, it is essential to draw pictures in order to understand which trigonometric function to use according to the angle that the vector in question forms with the component requested. For all of them try to picture a right angle triangle with the vector as the hypotenuse, and the components as the triangle's shorter sides. Please refer to the three pictures attached as image for this answer a,d notice that the vector quantity known for all cases is represented in red, and the component to find is represented in green.

Problem 1) : the vector velocity makes an angle of 24 degrees with the edge of the table. So picture that vector as the hypotenuse of a right angle triangle for which you know the value: 1.8 m/s

So in this case, where you know the angle, the hypotenuse, and need to find the adjacent side to the angle, you use the cosine function as follows:

requested component =1.8 * cos (24) =1.644 \frac{m}{s}

which we round to 1.6 to match answer C).

For problem 2.) wee need to find the component opposite to the given angle in the triangle for which we also know the hypotenuse. So we use the sine function as follows:

requested component =150 * sin(65) = 135.94 m

which we round to 135.9 m to match answer D).

For problem 3.) we need to find the horizontal component to the acceleration which corresponds to the adjacent side to the known angle, so we use the cosine function as follows:

requested component =12 *cos(50) = 7.71 \frac{m}{s^2}

which we round tp 7.7 to match answer A).

7 0
4 years ago
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