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UkoKoshka [18]
3 years ago
7

A small electric motor produces a force of 5 N that moves a remote-control car 5 m every second. How much power does the motor p

roduce? Give your answer in watts and horsepower.
Physics
2 answers:
PolarNik [594]3 years ago
5 0

Answer:

25 W

or

0.0335 hp

Explanation:

Power: This can be defined as the rate at which work is done. The S.I ubit of power is Watt(W).

The expression for Power in terms of force and velocity is given as,

P = F×V.................. Equation 1

Where P = Power, F = force of the electric motor, V = Velocity of electric motor

Given: F = 5 N, V = 5 m/s.

Substitute into equation 2

P = 5×5

P = 25 W.

P = 25 W

or

P = 25(0.00134) horse power

P = 0.0335 hp

Hence the motor produce a power of 25 W or 0.0335 hp

kati45 [8]3 years ago
4 0

Answer:

Explanation:

Given:

Force, f = 5 N

Velocity, v = 5 m/s

Power, p = energy/time

Energy = mass × acceleration × distance

Poer, p = force × velocity

= 5 × 5

= 25 W.

Note 1 watt = 0.00134 horsepower

But 25 watt,

0.00134 hp/1 watt × 25 watt

= 0.0335 hp.

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Musya8 [376]

Answer:

Second Choice.

Explanation:

Jack's Power = W/t

Jill's Power = 2W/(0.5)*t

2/0.5 = 4

Jill's Power = 4*W/t

Jill's Power is 4 times greater than Jack's

Second Choice

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3 years ago
To calculate the change in kinetic energy, you must know the force as a function of _______. The work done by the force causes t
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Answer:

(c) position

Explanation:

From the work-energy theorem, the workdone by a force on a body causes a change in kinetic energy of the body.

But, remember that the work done (W) by a force (F) on a body is the product of the force and the distance d, moved by the body caused by the force. i.e

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This distance is a measure of the position of the body at a given instance.

Therefore, the work done is given by the force as a function of distance (or position).

3 0
4 years ago
The potential difference between two equipotential lines 5.0 mm apart has a value of 1.2 V, calculate the electric field value.
jonny [76]

Answer:

The electric field value is 240 N/C

Explanation:

Given that,

Distance = 5.0 mm

Potential difference = 1.2 V

We need to calculate the electric field value

Using formula of potential difference

\Delta V=Ed

E=\dfrac{\Delta V}{d}

Where, E = electric field

V = potential difference

d = distance

Put the value into the formula

E=\dfrac{1.2}{5.0\times10^{-3}}

E= 240\ N/C

Hence, The electric field value is 240 N/C

6 0
3 years ago
Four students are each pushing on one side of a box. Mara is pushing to the west, Cindi is pushing to the east, Chris is pushing
jenyasd209 [6]

Answer:

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Explanation:

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