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Ivanshal [37]
3 years ago
12

A mass M is attached to a spring with spring constant k. When this system is set in motion with amplitude A, it has a period T.

What is the period if the mass is doubled to 2M
Physics
1 answer:
labwork [276]3 years ago
7 0

Answer:

T' = o.707T

Explanation:

T = 1/2\pi \sqrt{k/m} \\\\m'=2m then\\T' = 1/2\pi \sqrt{k/m'}\\    = 1/2\pi \sqrt{k/2m}\\T' = \frac{(1/2\pi \sqrt{k/m}\\)}{1.4} T' = \frac{T}{1.4}\\T' = 0.707T

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