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Ivanshal [37]
3 years ago
12

A mass M is attached to a spring with spring constant k. When this system is set in motion with amplitude A, it has a period T.

What is the period if the mass is doubled to 2M
Physics
1 answer:
labwork [276]3 years ago
7 0

Answer:

T' = o.707T

Explanation:

T = 1/2\pi \sqrt{k/m} \\\\m'=2m then\\T' = 1/2\pi \sqrt{k/m'}\\    = 1/2\pi \sqrt{k/2m}\\T' = \frac{(1/2\pi \sqrt{k/m}\\)}{1.4} T' = \frac{T}{1.4}\\T' = 0.707T

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Pls help ASAP !! Phyics
mina [271]

Answer:

Explanation:

Given

mass (m)= 20 kg

acceleration (a)= 10 m/s^2

Force (f)= m a

             = 20 * 10

            = 200 N

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Suppose Galileo dropped a lead ball (100 kilograms) and a glass ball (1 kilogram) from the Leaning Tower of Pisa. Which one hit
kodGreya [7K]

IF there is no air resistance, then he could drop a feather, a piece
of Kleenex, a school bus, and a battleship.  If he dropped them all
at the same time from the same height, they would all hit the ground
at the same time.

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4 years ago
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A net force acting on an object will always cause a change in the object's _________.
Nataly [62]
 cause a change in the object's velocity
3 0
3 years ago
How does something become charged using friction?​
KonstantinChe [14]

<u>Answer:</u>

"Where friction or rubbing results in the transfer of electrons between particles, objects can become negatively or positively charged."

<u>Explanation:</u>

The motion resistance of one moving object with respect to another is called as "Friction". It isn't a basic force, like gravity or electromagnetism. Alternatively, scientists believe it is the product of the electromagnetic attraction in two touching surfaces between charged particles.

The friction have formula:  

Friction force (<em>f </em>)  = coefficient of friction  × normal force (N)

For an instances when one ride a bicycle, an example of rolling friction is the contact between the wheel and the way.

4 0
4 years ago
To keep the calculations fairly simple, but still reasonable, we shall model a human leg that is 92.0 cm long (measured from the
lorasvet [3.4K]

Answer:

Xc = 64.27 cm, Yc = 0 cm, Xc = 27.73 cm, Yc = 18.27 cm

Explanation:

A human leg is 92 cm long equally divided into two parts (upper leg and lower leg) that is both are 46 cm long

M1 = 8.35 kg

M2 = 5.50 kg

A. Starting from hip joint, when the leg is placed horizontally, the X coordinate of centre of mass will be

Xc = (m1x1 + m2x2) / m1 + m2

Xc = (8.35x46 + 5.50 x 92) / 8.35 + 5.50

( here we took x2 = 92 cm because we are measuring length from the hip joint, that means length at hip joint is 0 and at the foot 92 cm)

Xc = 890.1 / 13.85

Xc = 64.27 cm

B. Yc = (y1m1 + y2m2) / m1 + m2

Yc = (0x8.35 + 0x5.50) / 8.35 + 5.50

( here y1 and y2 are 0 because the leg is placed horizontally that means in X direction so none of the leg component is in Y direction)

Yc = 0 cm

C. Xc = (m1x1 + m2x2) / m1 + m2

Xc = (8.35x46 + 5.50x0) / 8.35 + 5.50

(here x2 is taken 0 because the other half leg is bent vertically that means it is in Y direction so its X component is 0)

Xc = 384.1 / 13.85

Xc = 27.73 cm

D. Yc = (m1y1 + m2y2) / m1 + m2

Yc = (8.35x0 + 5.50x46) / 8.35 + 5.50

(here y1 is zero because the upper leg is in X direction and y2 is taken 46 cm because starting measuring from hip joint 46 cm of length of lower leg is in Y direction)

Yc = 253/13.85

Yc = 18.27 cm

7 0
3 years ago
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