The concentration of the HCl solution is 0.72 M.
<h3>How do we calculate the concentration?</h3>
Concentration of the required solution by the use of the known concentration solution will be determine by using the below equation as:
M₁V₁ = M₂V₂, where
- M₁ & V₁ are the molarity and volume of the HCl solution.
- M₂ & V₂ are the molarity and volume of the NaOH solution.
On putting values in the above equation, we get
M₁ = (1)(0.018) / (0.025) = 0.72 M
Hence required concentration of HCl is 0.72M.
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Explanation:
Since mole ratio of O2 : NH3 = 7 : 4,
Volume of NH3 = 50dm³ * 4/7 = 28.57dm³.
The reactant is what you begin with.
The product is what you end up with (so the answer is B)
Answer:
1, 3, 2
Explanation:
N2 + H2 → NH3
I usually find that the best way to systematically balance an equation by inspection is to start with the most complicated-looking formula and then balance atoms in the order:
- All atoms other than O and H
- O
- H
(a) The most complicated formula is NH3.
(b) Balance N.
We have 1 H in NH3, but 2 N on the left. We need 2 N on the right. Put a 1 in front of N2 and a 2 in front of NH3.
1N2 + H2 → 2NH3
(c) Balance H.
We have fixed 6 H on the right, so we need 6 H on the left. Put a 3 in front of H2.
1N2 + 3H2 → 2NH3
The equation is now balanced, and the coefficients are 1, 3, 2.
