<h3>
Answer:</h3>
7.51 × 10²² atoms S
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
4.00 g S
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of S - 32.07 g/mol
<u>Step 3: Convert</u>
- Set up:
- Multiply:
<u>Step 4: Check</u>
<em>Follow sig figs and round. We are given 3 sig figs.</em>
7.51107 × 10²² atoms S ≈ 7.51 × 10²² atoms S
Answer:
2 if u are doing what i think u are doing
Boiling-point elevation is a colligative property.
That means, the the boiling-point elevation depends on the molar content (fraction) of solute.
The dependency is ΔTb = Kb*m
Where ΔTb is the elevation in the boiling point, kb is the boiling constant, and m is the molality.
A solution of 6.00 g of Ca(NO3) in 30.0 g of water has 4 times the molal concentration of a solution of 3.00 g of Ca(NO3)2 in 60.0 g of water.:
(6.00g/molar mass) / 0.030kg = 200 /molar mass
(3.00g/molar mass) / 0.060kg = 50/molar mass
=> 200 / 50 = 4.
Then, given the direct proportion of the elevation of the boiling point with the molal concentration, the solution of 6.00 g of CaNO3 in 30 g of water will exhibit a greater boiling point elevation.
Or, what is the same, the solution with higher molality will have the higher boiling point.
The new temperature of the gas is 115 °C
From the question given above, the following data were obtained:
- Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K
- Initial pressure (P₁) = 0.96 atm
- New pressure (P₂) = 1.25 atm
- New temperature (T₂) =?
The new temperature of gas can be obtained as follow:
Therefore, the new temperature is 115 °C
Learn more about gas laws: brainly.com/question/25862018