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emmasim [6.3K]
3 years ago
9

What type of star has an absolute brightness of 5 and a surface temperature around 3,000 °C?

Chemistry
2 answers:
NikAS [45]3 years ago
7 0

Answer : The correct answer is option A : Supergiants

Explanation :

In the above graph absolute brightness is marked on y-axis and surface temperature is marked on x-axis.

To find out what type of star has an absolute brightness of 5 and a surface temperature around 3,000 °C, we will draw a straight line from x axis which represents a temperature of 3,000 °C and another straight line from y-axis which represents absolute brightness of 5.

From the attached graph we can see that these 2 lines meet in the region shown by Supergiants

Therefore we can say that, Supergiants has an absolute brightness of 5 and a surface temperature around 3,000 °C

pav-90 [236]3 years ago
3 0
From the graph. the answer is
A. supergiants
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Answer:- b. +3

Explanations:- Charge of a metal ion is equal to the number of valence electrons it has as it loses these electrons to have its nearest noble gas like electron configuration.

Al has 3 valence electrons and being a metal it loses all of these and so the charge of Al ion is +3. It could be shown as:

Al\rightarrow Al^+^3+3e^-

So, the right choice is b. 3+.

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Which shows the formula for an Organic acid
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Answer:
            The formula of Organic acid is as follow,

                                                 R-COOH

Explanation:
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                               RCOOH     ⇄    RCOO⁻  +  H⁺
Where;
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A particular laser consumes 130.0 Watts of electrical power and produces a stream of 2.67×1019 1017 nm photons per second.
solniwko [45]

The missing question is:

<em>What is the percent efficiency of the laser in converting electrical power to light?</em>

The percent efficiency of the laser that consumes 130.0 Watt of electrical power and produces a stream of 2.67 × 10¹⁹ 1017 nm photons per second, is 1.34%.

A particular laser consumes 130.0 Watt (P) of electrical power. The energy input (Ei) in 1 second (t) is:

Ei = P \times t = 130.0 J/s \times 1 s = 130.0 J

The laser produced photons with a wavelength (λ) of 1017 nm. We can calculate the energy (E) of each photon using the Planck-Einstein's relation.

E = \frac{h \times c }{\lambda }

where,

  • h: Planck's constant
  • c: speed of light

E = \frac{h \times c }{\lambda } = \frac{6.63 \times 10^{-34}J.s  \times 3.00 \times 10^{8} m/s }{1017 \times 10^{-9} m }= 6.52 \times 10^{-20} J

The energy of 1 photon is 6.52 × 10⁻²⁰ J. The energy of 2.67 × 10¹⁹ photons (Energy output = Eo) is:

\frac{6.52 \times 10^{-20} J}{photon} \times 2.67 \times 10^{19} photon = 1.74 J

The percent efficiency of the laser is the ratio of the energy output to the energy input, times 100.

Ef = \frac{Eo}{Ei} \times 100\% = \frac{1.74J}{130.0J} \times 100\% = 1.34\%

The percent efficiency of the laser that consumes 130.0 Watt of electrical power and produces a stream of 2.67 × 10¹⁹ 1017 nm photons per second, is 1.34%.

You can learn more about lasers here: brainly.com/question/4869798

8 0
3 years ago
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