Answer: -8+61 = 53 and 6+61 = 67
Answer:
0.6210
Step-by-step explanation:
Given that a Food Marketing Institute found that 39% of households spend more than $125 a week on groceries
Sample size n =87
Sample proportion will follow a normal distribution with p =0.39
and standard error = 
the probability that the sample proportion of households spending more than $125 a week is between 0.29 and 0.41
=
There is 0.6210 probability that the sample proportion of households spending more than $125 a week is between 0.29 and 0.41
Answer:
X probability = 0.02
Cumulative frequency at x ( 6 ) = 1
Step-by-step explanation:
X P ( X ) Cf ( X )
1 0.58 0.58
2 0.18 0.58 + 0.18 = 0.76
3 0.10 0.76 + 0.10 = 0.86
4 0.07 0.86 + 0.07 = 0.93
5 0.05 0.93 + 0.05 = 0.98
6 0.02 0.98 + 0.02 = 1
Well if you have three and add negative 3 it equals 0