Hi there!
Recall the equation for electric potential of a point charge:

V = Electric potential (V)
k = Coulomb's Constant(Nm²/C²)
Q = Charge (C)
r = distance (m)
We can begin by solving for the given electric potentials. Remember, charge must be accounted for. Electric potential is also a SCALAR quantity.
Upper right charge's potential:

Lower left charge's potential:

Add the two, and subtract from the total EP at the point:

The remaining charge must have a potential of 2036.25 V, so:

 
        
             
        
        
        
Answer:
See the answers below.
Explanation:
We can solve both problems using Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F =m*a
where:
F = force [N] (units of newtons)
m = mass = 1000 [kg]
a = acceleration = 3 [m/s²]
![F = 1000*3\\F=3000[N]](https://tex.z-dn.net/?f=F%20%3D%201000%2A3%5C%5CF%3D3000%5BN%5D)
And the weight of any body can be calculated by means of the mass product by gravitational acceleration.
![W=m*g\\W=1000*9.81\\W=9810 [N]](https://tex.z-dn.net/?f=W%3Dm%2Ag%5C%5CW%3D1000%2A9.81%5C%5CW%3D9810%20%5BN%5D)
 
        
             
        
        
        
just search up the answer/ definition to all of them, rephrase into own words, then do the same for examples.