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Zepler [3.9K]
3 years ago
5

A class of students performed the heat transfer experiment shown in the picture. In the experiment, three plastic dishes were pa

rtially filled with equal amounts of dark soil, light soil, and water. Thermometers were placed in each dish, and the dishes were placed under a heating lamp. The substances were left under the heating lamp for ten minutes, and their temperatures were observed and recorded. After recording the temperatures of the substances as they were heating, the students turned the lamp off and recorded the temperatures of the substances as they cooled for ten minutes.
Which method of heat transfer is illustrated in this experiment? Explain your answer

Physics
1 answer:
balandron [24]3 years ago
6 0

The method of heat transfer used in the experiment is radiation.

Radiation is a method of heat transfer in which there is no material medium that conveys heat. Heat travels through empty space and causes the temperature of objects to rise.

In this case, there was no material medium that conveyed heat from the lamp to the dishes containing the plants. Heat from the lamp traveled through space and reached the dishes. This is an example of heat transfer via radiation.

Learn more: brainly.com/question/12494464

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Answer:

C) 7.35*10⁶ N/C radially outward

Explanation:

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       E*A = \frac{Q_{enc} }{\epsilon_{0}} (1)

  • As the electric field must be zero inside the conducting spherical shell, this means that the charge enclosed by a spherical gaussian surface of a radius between 4 and 5 cm, must be zero too.
  • So, the +8 μC charge of  the solid conducting sphere of radius 2cm, must be compensated by an equal and opposite charge on the inner surface of the conducting shell of total charge -4 μC.
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        Q_{enc} = - 4e-6 C - (-8e-6 C) = + 4 e-6 C

  • Replacing in (1) A = 4*π*ε₀, and Qenc = +4 μC, we can find the value of E, as follows:

      E = \frac{1}{4*\pi*\epsilon_{0} } *\frac{Q_{enc} }{r^{2} } = \frac{9e9 N*m2/C2*4e-6C}{(0.07m)^{2} } = 7.35e6 N/C

  • As the charge that produces this electric field is positive, and the electric field has the same direction as the one taken by a positive test charge under the influence of this field, the direction of the field is radially outward, away from the positive charge.
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