Hello Again! I think the Answer might be 220 m! ( 1/2) ( 21 m/s + 0 m/s) (21 s) = 220 m
Earth's gravity pulls air as close to the surface as possible. As altitude increases, the amount of gas molecules in the air decreases—the air becomes less dense than air nearer to sea level.
To solve this problem we will use the definition of the kinematic equations of centrifugal motion, using the constants of the gravitational acceleration of the moon and the radius of this star.
Centrifugal acceleration is determined by

Where,
v = Velocity
r = Radius
From the given data of the moon we know that gravity there is equivalent to

While the radius of the moon is given by

If we rearrange the function to find the speed we will have to



The speed for this to happen is 1.7km/s
Answer:
vf = √(vi²+2*(F/m)*D)
Explanation:
Given
Mass of the particle: M
Initial speed of the particle: vi
Force: F
Distance: D
We can apply the formula
F = M*a ⇒ a = F/m
then we use the equation
vf = √(vi²+2*a*D)
⇒ vf = √(vi²+2*(F/m)*D)