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3 years ago

You have to run 2.2 miles in track. How far is that in feet? There are 5280 feet in 1 mile

Physics

1 answer:

Greeley [361]3 years ago

8 0

Answer:

$11616ft^{2}$ or 11616

Explanation:

Since there are 5280 feet in 1 mile

you do 2.2 × 5280

2.2 × 5280 = 11616

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An imaginary dense star z has 1/5 the radius of earth, but 1000 times the earths. how much would a mass weighing 1.0n on earth w

andrew11 [14]

A 1-newton mass on earth would be 1000 newtons on star Z.

Funny enough, stars like this exist~! They're called "Neutron Stars."

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3 years ago

a tuck at rest starts to move and accelerated by 4m/s in 25 secondd. what is the velocity of the truck at the end offf the time?

inysia [295]

Answer:

100m/s

Explanation:

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3 years ago

Read 2 more answers

The angle of elevation from a point on the ground to the top of a pyramid is 37 degrees 50' The angle of elevation from a point

Serjik [45]

Answer:

The height of the pyramid is approximately 104 Ft. See the graphic attached.

Explanation:

First, you have to plot to realize that you have two rectangle triangles, formed by the different elevation points of view. From there you can have a system of two equations, with two unknown values.

Equation (1)

$tan 37^{o}50'= \frac{Ph}{x} \\\\Ph=tan 37^{o}50' x= 0.7766 x$

Equation (2)

$tan 18^{o}10'=\frac{Ph}{x+183} \\\\Ph=[tan 18^{o}10'][x+183]=[0.3281][x+183]$

Matching (1) and (2)

$0.7766 x=0.3281(x+183)\\\\(0.7766-0.3281)x=60.05\\\\x=\frac{60.05}{0.4485} =133.89ft$

replacing x value in (1)

$Ph=0.7766*133.89=103.9789\\Ph = 104 ft$

5 0

3 years ago

A 600kg car is moving at 5 m/s to the right and elastically collided with a stationary 900 kg car. What is the velocity of the 9

11111nata11111 [884]

Answer:

$\mathrm{v}_{2} \text { velocity after the collision is } 3.3 \mathrm{m} / \mathrm{s}$

Explanation:

It says “Momentum before the collision is equal to momentum after the collision.” Elastic Collision formula is applied to calculate the mass or velocity of the elastic bodies.

$m_{1} v_{1}=m_{2} v_{2}$

$\mathrm{m}_{1} \text { and } \mathrm{m}_{2} \text { are masses of the object }$

$\mathrm{v}_{1} \text { velocity before the collision }$

$\mathrm{v}_{2} \text { velocity after the collision }$

$\mathrm{m}_{1}=600 \mathrm{kg}$

$\mathrm{m}_{2}=900 \mathrm{kg}$

$\text { Velocity before the collision } v_{1}=5 \mathrm{m} / \mathrm{s}$

$600 \times 5=900 \times v_{2}$

$3000=900 \times v_{2}$

$\mathrm{v}_{2}=\frac{3000}{900}$

$\mathrm{v}_{2}=3.3 \mathrm{m} / \mathrm{s}$

$\mathrm{v}_{2} \text { velocity after the collision is } 3.3 \mathrm{m} / \mathrm{s}$

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4 years ago

Physics. Need help. Brainlieast answer for most/ all of the answers answered

Mumz [18]

<u>ALL of the following work assumes NO AIR RESISTANCE:</u>

1). an object moving under the influence of only gravity, and not in orbit; its horizontal velocity is constant, and its vertical motion is accelerated downward at 9.8 m/s²

2). a parabola

3). Horizontal: velocity is constant, acceleration is zero. . . . Vertical: acceleration is 9.8 m/s² downward, velocity depends on whether it was launched, thrown up, thrown down, dropped, etc.

4). a). the one that was thrown horizontally; b). both hit the ground at the same time; c). both hit the ground with the same vertical velocity

5). a). zero; b). zero; c). gravity ... 9.8 m/s² down; d). 3.06 seconds; e). 4.38 m/s; f). 30 m/s g). no; gravity has no effect on horizontal motion

6). a). 1.8 seconds; b). 13.1 meters; c). 17.6 m/s down; d). 7.3 m/s; gravity has no effect on horizontal motion

7). 45 m/s

8). without air resistance, the ball is traveling horizontally at 13 km/hr, and it lands back in your hand

9). a). 4.49 m/s; b). 29.7 m/s

10). 7.24 meters

11). 700 meters

12). A). 103.7 meters ( ! she's in big trouble ! ); B). 17.5 meters

3 0

3 years ago