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3 years ago

When recording video footage, the camera needs to move horizontally along side a building. what type of movement is this?

1 answer:

4 0

The answer that fits in the blank is truck.

Inded, truck or trucking is moving the camera from one side to the other side to make the objects to appear closer or farther away.

There are some basic movements of the camera to record video footage: zoom, pan, tilt, dolly, truck, pedestal and rack focus.

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Air in human lungs has a temperature of 37.0°C and a saturation vapor density of 44.0 g/m³.

ioda

Answer:

(a). The maximum loss of water vapor by the person is $8.8\times10^{-2}\ g$

(b). The partial pressure of water vapor is $6.29\times10^{3}\ N/m^2$

Explanation:

Given that,

Temperature = 37.0°C

Volume of air = 2.00 L

Density of vapor = 44.0 g/m³

We need to calculate the maximum loss of water vapor by the person

Using formula of density

$m=\rho_{air}\times V_{air}$

Put the value into the formula

$m=44.0\times2.00\times10^{-3}$

$m=0.088\ g$

$m=8.8\times10^{-2}\ g$

(b). We need to calculate the partial pressure of water vapor

Using formula of pressure

$PV=nRT$

$P=\dfrac{nRT}{V}$

$P=\dfrac{\rho\times R\times T}{M}$

Put the value into the formula

$P=\dfrac{44\times8.314\times(37+273)}{18.01528}$

$P=6294.82\ N/m^2$

$P=6.29\times10^{3}\ N/m^2$

Hence, (a). The maximum loss of water vapor by the person is $8.8\times10^{-2}\ g$

(b). The partial pressure of water vapor is $6.29\times10^{3}\ N/m^2$

3 0

4 years ago

Explain a situation in which you can accelerate even though your speed doesn't change

ANTONII [103]

You can accelerate by changing direction, even though you don't speed up/down. Remember that acceleration is a vector so, it has a direction and a magnitude. That's why this works! Hope it helps.

4 0

4 years ago

Read 2 more answers

A college student is working on her physics homework in her dorm room. her room contains a total of 6.0×1026 gas molecules. as s

ella [17]

<span>6.6 degrees C Let's model the student as a 125 w furnace that's been operating for 11 minutes. So 125 w * 11 min = 125 kg*m^2/s^3 * 11 min * 60 s/min = 82500 kg*m^2/s^2 = 82500 Joule So the average kinetic energy increase of each gas molecule is 82500 J / 6.0x10^26 = 1.38x10^-22 J Now the equation that relates kinetic energy to temperature is: E = (3/2)Kb*Tk E = average kinetic energy of the gas particles Kb = Boltzmann constant (1.3806504Ă—10^-23 J/K) Tk = Kinetic temperature in Kelvins Notice the the energy level of the gas particles is linear with respect to temperature. So we don't care what the original temperature is, we just need to know by how much the average energy of the gas particles has increased by. So let's substitute the known values and solve for Tk E = (3/2)Kb*Tk 1.38x10^-22 J = (3/2)1.3806504Ă—10^-23 J/K * Tk 1.38x10^-22 J = 2.0709756x10^-23 J/K * Tk 6.64 K = Tk Rounding to 2 significant digits gives 6.6K. So the temperature in the room will increase by 6.6 degrees K or 6.6 degrees C, or 11.9 degrees F.</span>

7 0

3 years ago

Use this formula to solve this problem: Power (P) = Work (W) ÷ time (t) Peter's body supplies a force of 500 N to run up a 5 met

sesenic [268]

As you said p=w/t.
but, w=f×s
=500×5=2500j
t=10s
p=w/t
=2500/10=250 watts

4 0

3 years ago

A circuit has a 10 Ω resistor connected to a 1.5 V dry cell. What is the current that can flow in the circuit?

ludmilkaskok [199]

Here is the highly detailed, arcane, complex, technical form of Ohm's Law that is needed in order to answer this question ===> I = V / R .

Current = (voltage) / (resistance)

Current = (1.5 V) / (10 Ω)

<em>Current = 0.15 Ampere</em>

8 0

3 years ago