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Pie
3 years ago
11

When recording video footage, the camera needs to move horizontally along side a building. what type of movement is this?

Physics
1 answer:
dmitriy555 [2]3 years ago
4 0
The answer that fits in the blank is truck.

Inded, truck or trucking is moving the camera from one side to the other side to make the objects to appear closer or farther away.

There are some basic movements of the camera to record video footage: zoom, pan, tilt, dolly, truck, pedestal and rack focus.
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The Sun's angular diameter is measured to be

The distance of the sun from the earth is 1.496 × m.

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A wave is moving between two mediums, as shown in the diagram below. The
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Uhm i think its a

Explanation:

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3 years ago
The lower the value of the coefficient of friction,the_the resistance to sliding​
malfutka [58]

Answer:

lower

Explanation:

The lower the value of the coefficient of friction, the lower the resistance to sliding.

The coefficient of friction is the ratio of the frictional force and the normal force pressing two surfaces in contact together.

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U is the coefficient of friction

F is the frictional force

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 We see that coefficient of friction is directly proportional to frictional force.

7 0
3 years ago
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kozerog [31]

Newton's second equation of motion :-

S=ut+1/2at^2 [where, u is the initial velocity, a is the acceleration and t is the time interval]

This Equation simply finds a relation between distance travelled by a particle (classically) under uniform acceleration.

So let's see what pieces of information (bundles of equations) do we have with us, initially.

We have, a very primary equation with us,

dS/dt = v… (I)

(Considering motion in a straight line only)

And we also have the equation

dv/dt = a…(II)

Simply replacing the v in eqn (II) by eqn (I), we find

d2S/dt^2 = a…(III)

This is what we need to solve. It's easy.

You know,

d2S/dt^2 = d/dt(dS/dt) = a

⟹ dS/dt = ∫adt = at+c1

Since, dS/dt is the velocity of the particle,

Therefore, at t = 0, dS/dt|t = 0 = u

⟹ u = a∗0 + c1 = c1

⟹ c1 = u

Therefore, dS/dt = u + at

Thus, S = ∫(udt + atdt)

⟹ S = ut + 1/2at^2 +c^2

If say, the particle is already having a displacement S0 the moment you start measuring it's motion. Then, at t = 0, S = S0

This makes S = S0 +ut + 1/2at^2

Since, in most of the practical cases, we start measuring a motion when the particle starts displacing (i.e., when S0=0 ),

We get

S = ut + 1/2at^2

Hope it helps :)

5 0
3 years ago
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Answer:

You use a force of 150 N to push a 30 kg crate across the floor for a distance of 10 m. If the crate is moving at a speed of 5 m/s…

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