Answer:
Distance = πr
Displacement = 2r
Explanation:
First we need to find the distance covered by the car. As the car is travelling on a circular path and it traveled to a diametrically opposite point on the circular path. Therefore, the distance covered by the car must be the half value of the circumference.
Distance = Circumference/2
Distance = 2πr/2
<u>Distance = πr</u>
Since, displacement is the straight line distance between two points. So, the displacement in moving from a point to its diametrically opposite point must be equal to the diameter of circle:
Displacement = Diameter
<u>Displacement = 2r</u>
The speed of light (electromagnetic radiation) is equal to 299 792 458
m / s or 3x10^8 m/s in scientific notation.
So with this information, we could now look for the
distance. Solution:
Take note that μs means microseconds.
Speed of light * microseconds travelled * actual amount of microseconds
(3x10^8 m/s) (45.0 μs) (1x10^-6 s/μs) = 13,500 m.
In light of this, V=V 0 loge (r/r 0 ) Field E= dr dV =V 0(r0r) eE= r mV2 alternatively, reV0r0=rmV2. V=(m eV 0 r 0 ) \ s1 / 2mV=(m e V 0 r 0 ) 1/2 = constant mvr= 2 nh, also known as Bohr's quantum condition or Hermitian matrix.
Show that the eigenfunctions for the Hermitian matrix in review exercise 3a can be normalized and that they are orthogonal.
Demonstrate how the pair of degenerate eigenvalues for the Hermitian matrix in review exercise 3b can be made to have orthonormal eigenfunctions.
Under the given Hermitian matrix, "border conditions," solve the following second order linear differential equation: d2x/ dt2 + k2x(t) = 0 where x(t=0) = L and dx(t=0)/ dt = 0.
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