To find the volume of a box-shaped fish trap, we have to multiply the three dimensions of it:
(1/4 m)* (2/3 m)* (3/5 m)
= (1*2*3)/ (4*3*5) m^(3)
= 6/ 60 m^(3)
= 1/10 m^(3)
= 0.1 m^(3)
The volume of the box-shaped fish trap is 0.1 m^(3).
Hope this is helpful~
Answer:
71°
Step-by-step explanation:
In order to be able to solve this problem, we must assume the relation between lines "a" and "b" is that they are parallel.
If a║b, then ∠1 and ∠2 are corresponding, hence congruent.
m∠1 = m∠2 = 71°
Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S = 
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer
To find the number of hours, divide the total distance by the speed.
Hours = 76 km / 14 km per hour
Hours = 4.529
Round the answer as needed.
Step-by-step explanation:
the steeper line is y = 6x + 11 because its gradient 6, is bigger than 3
