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Vedmedyk [2.9K]
3 years ago
13

A system for which the steady state error is zero for a unit-step is of type (A) Zero (B) 1 (C)2 (D) 1 or 2 (E) none of above

Engineering
1 answer:
denpristay [2]3 years ago
8 0

Answer:

(E) 1 or  2

Explanation:

Steady state error for unit step input is given by e_{ss}=\frac{1}{1+k_p} where K_P is position error coefficient the value of  K_P is given by k_p=\lim_{s\rightarrow 0}G(s) it will be only finite when the type of the open loop system will be 0 when the of the system will be 1 or 2 then k_p becomes infinite and steady state error will become zero so the option (E) will be the correct answer

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