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Flauer [41]
3 years ago
11

Act as food engineers or biomedical engineers and write a short paragraph explaining why they need to know about mixtures and so

lutions in creating new food products or medicines.
Engineering
1 answer:
drek231 [11]3 years ago
5 0

Answer:

We use our knowledge of mixtures and solutions when we are designing new synthetic materials. This is especially the case in the biomedical field, where we have to deal with compatibility issues when placing materials made outside the human body into the body.We also design ways to help separate mixtures and solutions in industrial, commercial and environmental processes.

Hope this helps

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a poorly tighten terminal is often the cause of a/an ? a) open circuit b) circuit breaker interrupt c)short circuit d) ground fa
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Answer: b) circuit breaker interrupt

Explanation:

Wires connect to outlets through terminals and these terminals need to be tight to ensure that electricity flows with the minimum amount of resistance.

If the terminal is poorly tightened, what happens is that resistance will build up as the appliance is being used and this resistance will make the terminal hotter.

The heat will continue to rise until the circuit breaker trips to interrupt the circuit and protect the appliance.

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3 years ago
A soil sample has a moist unit weight of 117 pcf, a moisture content of 17 percent, and soil particles with a specific gravity o
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Answer:

(A) Dry unit weight. = 15.71 kN/m³ =100.91 pcf

(B) Porosity = 40.82 %

(C) Degree of saturation = 66.52 %

(D) Weight of water, in pounds per cubic foot, to be added to reach full saturation = 81.22 pcf

Explanation:

(A) γd =\frac{\gamma }{1+w} = \frac{18.379}{1+.17} = 15.71 KN/m³

(B) \gamma _d =\frac{G_{s}* \gamma _w }{1+e} therefore  1+e = \frac{G_{s}* \gamma _w }{\gamma _d } \frac{2.7*9.81}{15.71} = 1.69

Therefore e = 0.69 and

Porososity n = \frac{e}{1+e} =\frac{0.69}{1+0.69} × 100% = 40.82 %

(C)  S_{e}  = w*G_{s} therefore S =\frac{w*G_{s}}{e} = \frac{0.17*9.81}{0.69}×100 = 66.52 %

(D) \gamma _{sat} =\frac{(G_{s}+e) \gamma_{w}  }{1+e} = \frac{(2.7+0.69)9.81}{1+0.69} = 19.68 kN/m³

The required amount of water is found from γ =ρ×g

ρ mass of water = \frac{\gamma}{g}  = \frac{(19.68-18.38)\frac{kN}{m^{3} } }{9.81 kg\frac{m}{s^{2} } } *\frac{1000 N}{kN} *\frac{9.81 kg\frac{m}{s^{2} } }{N} = 1301 \frac{kg}{m^{3} }

1 kg/m³ = 0.062 pcf therefore 1301 kg/m³ = 1301 ×0.062 pcf or 81.22 pcf

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3 years ago
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Answer:

A moving player may only take 2 legal steps after catching the ball to shoot, pass or to come to a stop.

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