Question

Sor-rey for posting again,I messed up on my last one...anyway,100 points and Brainlest! Please help ASAP!

Answer 1

The answer of 4(2x^3 y^4 )^4/2(2x^2 y^6 )^3  after simplification will be

4 $x^{6} y^{-2}$

Step-by-step explanation:

To simplify

$\frac{4(2x^3 y^4 )^4}{2(2x^2 y^6 )^3}$ .

Using exponential law the exponents of variables will be added when multiplied as per rule

we get

$\frac{4[(2^4)(x^{3\times 4}) ( y^{4\times4} )] }{2[(2^3)(x^{2\times3} ) (y^{6\times3} )]}$

$\frac{4[(16)(x^{12}) ( y^{16} )] }{2[(8)(x^{6} ) (y^{18} )]}\\\\\frac{64x^{12}y^{16} }{16 x^{6}y^{18} }$

Now by dividing according to exponential rule the exponents of variables will be subtracted as per rule

$(\frac{64}{16} ) x^{12-6} y^{16-18} \\4 x^{6} y^{-2}$

So the answer of 4(2x^3 y^4 )^4/2(2x^2 y^6 )^3  after simplification will be

4 $x^{6} y^{-2}$

Keywords: Algebra

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