Answer:
547.7 g of C₆H₁₂O₆
Solution:
The balance chemical equation is as follow,
C₆H₁₂O₆ + 6 O₂ → 6 CO₂ + 6 H₂O
According to equation,
6 moles of O₂ burns = 180.56 g of C₆H₁₂O₆
So,
18.2 moles of O₂ will burn = X g of C₆H₁₂O₆
Solving for X,
X = (18.2 mol × 180.56 g) ÷ 6 mol
X = 547.7 g of C₆H₁₂O₆
Answer:
<u>2</u> XE + <u>1</u> AB. --> <u>1</u> AE2 + <u>2</u> XB
Above equation is now balanced
First we find for the wavelength of the photon released due
to change in energy level. We use the Rydberg equation:
1/ʎ = R [1/n1^2 – 1/n2^2]
where,
ʎ is the wavelength
R is the rydbergs constant = 1.097×10^7 m^-1
n1 is the 1st energy level = 1
n2 is the higher energy level = infinity, so 1/n2 = 0
Calculating for ʎ:
1/ʎ = 1.097×10^7 m^-1 * [1/1^2 – 0]
ʎ = 9.1158 x 10^-8 m
Then calculate the energy using Plancks equation:
E = hc/ʎ
where,
h is plancks constant = 6.626×10^−34 J s
c is speed of light = 3x10^8 m/s
E = (6.626×10^−34 J s * 3x10^8 m/s) / 9.1158 x 10^-8 m
E = 2.18 x 10^-18 J = 2.18 x 10^-21 kJ
This is still per atom, so multiply by Avogadros number =
6.022 x 10^23 atoms / mol:
E = (2.18 x 10^-21 kJ / atom) * (6.022 x 10^23 atoms /
mol)
E = 1312 kJ/mol
Answer:
About one valence electron
Explanation:
Obviously, removing that electron gives us [Ar] (same configuration as K1+), which is a noble gas and has 8 electrons. Valence electrons are generally regarded as being 'the outermost electrons' for a given atom. Therefore, with neutral potassium, there is one valence electron
Answer: (3)
Medeleev arranged elements in order of increasing atomic weight and similar properties
He noticed that similar elements were grouped together by using this.
