(-5,1)(6,-2)
slope = (-2-1) / (6-(-5) = -3/(6 + 5) = -3/11
y = mx + b
slope(m) = -3/11
(-5,1)...x = -5 and y = 1
now we sub and find b, the y int
1 = -3/11(-5) + b
1 = 15/11 + b
1 - 15/11 = b
11/11 - 15/11 = b
-4/11 = b
equation in slope int form : y = -3/11x - 4/11
3/11x + y = - 4/11....multiply by 11
3x + 11y = -4 <== standard form
(4,-2)(4,8).....if u will notice, both the x values are the same. This means the lines are vertical with an undefined slope. Your equation is : x = 4.
Answer:
y = x + 2
Step-by-step explanation:
Slope-Intercept Form: y = mx + b
Slope Formula:
Step 1: Find slope <em>m</em>
m = (1 - 6)/(-1 - 4)
m = -5/-5
m = 1
y = x + b
Step 2: Find y-int <em>b</em>
y = x + b
1 = -1 + b
b = 2
Step 3: Rewrite equation
y = x + 2
I can’t find the answer. Are you sure this is the whole question?
A regular polygon has about 5 lines of symmetry. The number of lines of symmetry is equivalent to the number of sides.