Question

Hydrogen atom number 1 is known to be in the 4f state. Hydrogen atom number 2 is in the 5d state.

Answer 1

Answer:

4f   E₄ = 0.85 eV,    L₄ = 4.22 10⁻³⁴ ,  

5d          E₅ = 0.544 eV ,    L5 = 5.28 10⁻³⁴

Explanation:

Let's use the Bohr model, stable the energy of the hydrogen atom

              E = -13.606 / n2

where Eo = 13.606 eV is the energy of the ground states.

a) the energy of each atom

level 4f

In this nomenclature enumeration is the number n

               E = -13606 / 42

               E₄ = 0.85 eV

level 5d

                E₅ = -13.606 / 5 2

                E₅ = 0.544 eV

b) The angular momentum is given in Boh's model

                     L = n h / 2pi

let's calculate

             

level 4f             L₄ = 4 6.63 10⁻³⁴-34 / 2 pi

                        L₄ = 4.22 10⁻³⁴

level 4d

                       L5 = 5 6.63 10-⁻³⁴ / 2pi

                       L5 = 5.28 10⁻³⁴

c) The hydrogen atom in state n = 5 has lower energy than the other state

d) Atom 1 has less angular momentum than atom 2