Chloroplasts and vacuoles
Answer:
Average speed, As = 2.2 [m/s]
Explanation:
To solve these types of problems we must remember that the average of the speeds is determined by dividing the distance over time.
With the first speed and the time of 6 [s] we can calculate the distance.
V = x/t
where:
x = distance [m]
V = velocity = 1.1 [m/s]
t = time = 6 [s]
x1 = V*t
X1 = 1.1*6
X1 = 6.6 [m]
Now with the second velocity and 6 [s], we can calculate the second distance.
X2 = 3.3*6
X2 = 19.8 [m]
Now we have to calculate the average speed. The total distance is x = x1 +x2
X = 19.8 + 6.6 = 26.4 [m]
and the total time is 12 [s]
Therefore:
As = 26.4/12
As = 2.2 [m/s]
Let the rod be on the x-axes with endpoints -L/2 and L/2 and uniform charge density lambda (2.6nC/0.4m = 7.25 nC/m).
The point then lies on the y-axes at d = 0.03 m.
from symmetry, the field at that point will be ascending along the y-axes.
A charge element at position x on the rod has distance sqrt(x^2 + d^2) to the point.
Also, from the geometry, the component in the y-direction is d/sqrt(x^2+d^2) times the field strength.
All in all, the infinitesimal field strength from the charge between x and x+dx is:
dE = k lambda dx * 1/(x^2+d^2) * d/sqrt(x^2+d^2)
Therefore, upon integration,
E = k lambda d INTEGRAL{dx / (x^2 + d^2)^(3/2) } where x goes from -L/2 to L/2.
This gives:
E = k lambda L / (d sqrt((L/2)^2 + d^2) )
But lambda L = Q, the total charge on the rod, so
E = k Q / ( d * sqrt((L/2)^2 + d^2) )
Answer:
A mixture of blue & red light.
Explanation:
During photosynthesis, the oxygen delivered emanates from water particles and if a weighty isotope of oxygen atom was noticed in delivered sub-atomic oxygen, the water atoms were marked with the hefty isotope.
In order to maximize the growth rate of the plant, the required wavelength of light to be used is a mixture of blue & red light. This is on the grounds that as the absorption optima of plant's photoreceptors are at wavelength frequency of red and blue light, subsequently the combination of red and blue light would be ideal for plant growth and development.
The productivity of red (650–665 nm) LEDs on plant development is straightforward on the grounds that these wavelength frequencies entirely fit with the retention pinnacle of chlorophylls and phytochrome, while the enhanced blue light presented the possibility that development under regular light could be mirrored utilizing blue and red LEDs with negligible use of energy.
