Question

Find the difference. 9/x^2-9x-6/x^2-81

Answer 1

Assuming you mean $\frac{9}{x^2-9}- \frac{6}{x^2-81}$

we need to make denomeoator the same
multiply left fraction by $\frac{x^2-81}{x^2-81}$ and right fraction by $\frac{x^2-9}{x^2-9}$

we get
$\frac{9(x^2-81)}{(x^2-81)(x^2-9)}- \frac{6(x^2-9)}{(x^2-9)(x^2-81)}$
add
$\frac{9(x^2-81)-6(x^2-9)}{(x^2-81)(x^2-9)}$
expand top
$\frac{9x^2-729-6x^2+54}{(x^2-81)(x^2-9)}$
simplfiy
$\frac{3x^2-675}{(x^2-81)(x^2-9)}$

Answer 2

With Tiger Adding Fractions; {(9/(x^2-9x))-(6/(x^2-81))} Comparing Fractions; ... Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B) ... To calculate equivalent fraction , multiply the Numerator of each fraction, ... hope this helped i guess