A scooter consumes 28 liters of petrol for 2100 km how much petrol required to cover 3600km

pishuonlain [190]

Email them ..they will help you

https://blog.brainly.in/contact/

3 0

2 years ago

An airplane left Atlanta with 20 empty seats. If the airplane was 75% full, what was the total number of seats on the airplane?

jek_recluse [69]

Answer is <span>C. 80

hope that helps

75% are full with 20 seats empty so </span>20 seats empty = 25%

75% * 20 / 25% = 60

8 0

3 years ago

You install 638 feet of fencing along the perimeter of a rectangular yard. The width of the yard is 152 feet. What is the length

vovikov84 [41]

The length is 486

Step-by-step explanation:

638 subtract 152

6 0

3 years ago

QUESTION B ONLY PLEASE METHOD TOO

atroni [7]

Answer:

5

Step-by-step explanation:

We can express 125 as 5 x 5 x 5. Therefore, the value of the cube root of 125 is 5.

$\sqrt[3]{125} = \sqrt[3]{5 \times 5 \times 5} = 5$

8 0

3 years ago

A drug company is considering marketing a new local anesthetic. The effective time of the anesthetic the drug company is current

vladimir2022 [97]

Answer:

$z=\frac{7.1-7.4}{\frac{1.2}{\sqrt{36}}}=-1.5$

Since is a left sided test the p value would be:

$p_v =P(z$

Comparing the p value and the significance level given $\alpha=0.1$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the true mean is significantly lower than 7.4 minutes at 10% of significance

Step-by-step explanation:

Data given and notation

$\bar X=7.1$ represent the sample mean

$\sigma=1.2$ represent the population standard deviation

$n=36$ sample size

$\mu_o =7.4$ represent the value that we want to test

$\alpha=0.1$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean i lower than 7.4, the system of hypothesis would be:

Null hypothesis: $\mu \geq 7.4$

Alternative hypothesis: $\mu < 7.4$

The statistic is given by

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{7.1-7.4}{\frac{1.2}{\sqrt{36}}}=-1.5$

P-value

Since is a left sided test the p value would be:

$p_v =P(z$

Conclusion

Comparing the p value and the significance level given $\alpha=0.1$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the true mean is significantly lower than 7.4 minutes at 10% of significance

6 0

3 years ago