Question

A 7.45 nC charge is located 1.66 m from a 4.22 nC point charge. (a) Find the magnitude of the electrostatic force that one charge exerts on the other.(b) Is the force attractive or repulsive?i. attractiveii. repulsive

Answer 1

Answer:

a.$F=1.03\times 10^{-7}N$

b.Repulsive

Explanation:

We are given that

$q_1=7.45nC=7.45\times 10^{-9}C$

$1nC=10^{-9}C$

$q_2=4.22nC=4.22\times 10^{-9}C$

r=1.66m

We know that

Electrostatic force =$F=k\frac{q_1q_2}{r^2}$

r=Distance between $q_1\;and\;q_2$

k=Constant=$9\times 10^9Nm^2C^{-2}$

Using the formula

a.The magnitude of the electrostatic force=$F=\frac{9\times 10^9\times 7.45\times 10^{-9}\times 4.22\times 10^{-9}}{(1.66)^2}$

The magnitude of the electrostatic force=$F=1.03\times 10^{-7}N$

b.Both charge are positive .We know that when like charges repel each other and unlike charges attract to each other.

Therefore, the force between given charges is repulsive.